In a designed reversed curve the length of the common tangent is 150m thus the angle of intersection of both curves are 30degrees and 42degrees respectively, where the radius of the first curve is 125m, find the tangent distance of the first curve and the second curve. If the stationing of V1 is 10+120 find the stationing of PT using arc basis.
In a designed reversed curve the length of the common tangent is 150m thus the angle of intersection of both curves are 30degrees and 42degrees respectively, where the radius of the first curve is 125m, find the tangent distance of the first curve and the second curve. If the stationing of V1 is 10+120 find the stationing of PT using arc basis.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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In a designed reversed curve the length of the common tangent is 150m thus the angle of intersection of both curves are 30degrees and 42degrees respectively, where the radius of the first curve is 125m, find the tangent distance of the first curve and the second curve. If the stationing of V1 is 10+120 find the stationing of PT using arc basis.
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