+= /h(t) = -3 1-21-1 -21-110 Suppose a function h is giving by the Pollowing tabic of Values. 2h (-3)= 6 1 2 3 -4-26-1 2n(-2) +h (1) = h(2)-

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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## Function Table and Exercises

### Given Table of Values

The function \( h \) is defined by the following table:

\[
\begin{array}{|c|c|c|c|c|c|c|c|}
\hline
t & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\
\hline
h(t) & -2 & -1 & 0 & -4 & -2 & 6 & -1 \\
\hline
\end{array}
\]

### Exercises

1. Calculate \( 2h(-3) \):

2. Evaluate \( 2h(-2) + h(1) \):

3. Find the value of \( h(2) \):

4. Determine \( h(3) + h(1) \):

These exercises are designed to enhance your understanding of function tables and basic operations with functions.
Transcribed Image Text:## Function Table and Exercises ### Given Table of Values The function \( h \) is defined by the following table: \[ \begin{array}{|c|c|c|c|c|c|c|c|} \hline t & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\ \hline h(t) & -2 & -1 & 0 & -4 & -2 & 6 & -1 \\ \hline \end{array} \] ### Exercises 1. Calculate \( 2h(-3) \): 2. Evaluate \( 2h(-2) + h(1) \): 3. Find the value of \( h(2) \): 4. Determine \( h(3) + h(1) \): These exercises are designed to enhance your understanding of function tables and basic operations with functions.
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