he riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If diameter of hole equals diameter of rivet, what is the net area of edge-1-3-4-edge in square millimeters? a. 2685.5 b. 2752.5 c. 2792.4 d. 2632.96 2. If diameter of hole equals diameter of rivet, what is the net area of edge-1-2-3-4-edge in square millimeters? a. 5325 b. 4685 c. 2890 d. 3080 3. What is the limiting value of the net area for this steel element with hole (square mm) a. 2880 b. 2646 c. 2856 d. 2080 4. If allowable rupture stress in holes is Fu/2 where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534.5 kN b. 560.5 kN c. 546.5 kN d. 550.5 kN
he riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If diameter of hole equals diameter of rivet, what is the net area of edge-1-3-4-edge in square millimeters? a. 2685.5 b. 2752.5 c. 2792.4 d. 2632.96 2. If diameter of hole equals diameter of rivet, what is the net area of edge-1-2-3-4-edge in square millimeters? a. 5325 b. 4685 c. 2890 d. 3080 3. What is the limiting value of the net area for this steel element with hole (square mm) a. 2880 b. 2646 c. 2856 d. 2080 4. If allowable rupture stress in holes is Fu/2 where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534.5 kN b. 560.5 kN c. 546.5 kN d. 550.5 kN
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm.
1. If diameter of hole equals diameter of rivet, what is the net area of edge-1-3-4-edge in square millimeters?
a. 2685.5
b. 2752.5
c. 2792.4
d. 2632.96
2. If diameter of hole equals diameter of rivet, what is the net area of edge-1-2-3-4-edge in square millimeters?
a. 5325
b. 4685
c. 2890
d. 3080
3. What is the limiting value of the net area for this steel element with hole (square mm)
a. 2880
b. 2646
c. 2856
d. 2080
4. If allowable rupture stress in holes is Fu/2 where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity.
a. 534.5 kN
b. 560.5 kN
c. 546.5 kN
d. 550.5 kN
Transcribed Image Text:3075 mm
Rivets are 20 mm
snug fit
3075
13
280
12 mm thick plate
of
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