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- has greatest 1. By the comparison among pipeline, superpipeline, and superscalar. The speed up factor. a) superpipeline b) superscalar 2. The Wilkes control technique is a a) vertical b) orthogonal c) pipeline microprogramming d) pipeline and superscalar format. -c) Horizontal d) Variable format 3. The result of implementing booth's algorithm for multiplicand register and multiplier register of a hardware circuit (11101) and (1100). The result is 11101 a) (-12)d b) (812)d c) (12)d d) (-812)d 1100 4. In signed-magnitude binary division, if the dividend is (11100) and divisor is (10011) then the result is a) (10100) b) (00100) c) (11001) d) (01100) 5. The disadvantages of the hardwired approach are a) It is less b) It cannot be used for c) It is costly complex instructions d) less flexible & cannot be used for complex instructions flexible 6. The IEEE 32-bit floating-point number (0 10000010 10001100000000000000000) represent of: d) None of the mentioned a) 4.375 b) 12.375 c) 2.105497145E39 7. The registers are involves in the interrupt cycle are: a) MAR, MBR, (b) MAR, MBR, c) MAR, MBR, Control unit d) MAR, MBR PC IR 8. The Multi-processor organization of the symmetric multiprocessor (SMP) system are a) SISD b) MIMD c) SIMD d) MISD 9. The sequencing techniques categories of the microinstruction control unit are: b) branch taken, Two address fields, Single address field, Variable format branch never taken c) Check for zeros, Align the significands, d) None of the mentioned 10. Execute the instruction: BSA X: X is memory location, need: a) 5 steps and 5 b) 3 steps and 5 c) 3 steps and 3 d) 5 steps and 3 u operations u operations operations operations

- has greatest 1. By the comparison among pipeline, superpipeline, and superscalar. The speed up factor. a) superpipeline b) superscalar 2. The Wilkes control technique is a a) vertical b) orthogonal c) pipeline microprogramming d) pipeline and superscalar format. -c) Horizontal d) Variable format 3. The result of implementing booth's algorithm for multiplicand register and multiplier register of a hardware circuit (11101) and (1100). The result is 11101 a) (-12)d b) (812)d c) (12)d d) (-812)d 1100 4. In signed-magnitude binary division, if the dividend is (11100) and divisor is (10011) then the result is a) (10100) b) (00100) c) (11001) d) (01100) 5. The disadvantages of the hardwired approach are a) It is less b) It cannot be used for c) It is costly complex instructions d) less flexible & cannot be used for complex instructions flexible 6. The IEEE 32-bit floating-point number (0 10000010 10001100000000000000000) represent of: d) None of the mentioned a) 4.375 b) 12.375 c) 2.105497145E39 7. The registers are involves in the interrupt cycle are: a) MAR, MBR, (b) MAR, MBR, c) MAR, MBR, Control unit d) MAR, MBR PC IR 8. The Multi-processor organization of the symmetric multiprocessor (SMP) system are a) SISD b) MIMD c) SIMD d) MISD 9. The sequencing techniques categories of the microinstruction control unit are: b) branch taken, Two address fields, Single address field, Variable format branch never taken c) Check for zeros, Align the significands, d) None of the mentioned 10. Execute the instruction: BSA X: X is memory location, need: a) 5 steps and 5 b) 3 steps and 5 c) 3 steps and 3 d) 5 steps and 3 u operations u operations operations operations

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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- has greatest 1. By the comparison among pipeline, superpipeline, and superscalar. The speed up factor. a) superpipeline b) superscalar 2. The Wilkes control technique is a a) vertical b) orthogonal c) pipeline microprogramming c) Horizontal d) pipeline and superscalar format. d) Variable format 3. The result of implementing booth's algorithm for multiplicand register and multiplier register of a hardware circuit (11101) and (1100). The result is b) (812)d Illel a) (-12)d c) (12)d d) (-812)d 1100 4. In signed-magnitude binary division, if the dividend is (11100) and divisor is (10011) then the result is a) (10100) b) (00100) c) (11001) d) (01100) 5. The disadvantages of the hardwired approach are a) It is less b) It cannot be used for c) It is costly d) less flexible & cannot be used complex instructions flexible for complex instructions 6. The IEEE 32-bit floating-point number (0 10000010 10001100000000000000000) represent of: a) 4.375 b) 12.375 d) None of the mentioned c) 2.105497145E39 7. The registers are involves in the interrupt cycle are: a) MAR, MBR, (b) MAR, MBR, (c) MAR, MBR, Control unit d) MAR, MBR PC IR 8. The Multi-processor organization of the symmetric multiprocessor (SMP) system are a) SISD b) MIMD c) SIMD d) MISD 9. The sequencing techniques categories of the microinstruction control unit are: b) branch taken, (a) Two address fields, Single address field, Variable format 10. Execute the instruction: branch never taken c) Check for zeros, Align the significands, d) None of the mentioned BSA X: X is memory location, need : b) 3 steps and 5 c) 3 steps and 3 a) 5 steps and 5 μ operations d) 5 steps and 3 μ operations u operations u operations
Transcribed Image Text:- has greatest 1. By the comparison among pipeline, superpipeline, and superscalar. The speed up factor. a) superpipeline b) superscalar 2. The Wilkes control technique is a a) vertical b) orthogonal c) pipeline microprogramming c) Horizontal d) pipeline and superscalar format. d) Variable format 3. The result of implementing booth's algorithm for multiplicand register and multiplier register of a hardware circuit (11101) and (1100). The result is b) (812)d Illel a) (-12)d c) (12)d d) (-812)d 1100 4. In signed-magnitude binary division, if the dividend is (11100) and divisor is (10011) then the result is a) (10100) b) (00100) c) (11001) d) (01100) 5. The disadvantages of the hardwired approach are a) It is less b) It cannot be used for c) It is costly d) less flexible & cannot be used complex instructions flexible for complex instructions 6. The IEEE 32-bit floating-point number (0 10000010 10001100000000000000000) represent of: a) 4.375 b) 12.375 d) None of the mentioned c) 2.105497145E39 7. The registers are involves in the interrupt cycle are: a) MAR, MBR, (b) MAR, MBR, (c) MAR, MBR, Control unit d) MAR, MBR PC IR 8. The Multi-processor organization of the symmetric multiprocessor (SMP) system are a) SISD b) MIMD c) SIMD d) MISD 9. The sequencing techniques categories of the microinstruction control unit are: b) branch taken, (a) Two address fields, Single address field, Variable format 10. Execute the instruction: branch never taken c) Check for zeros, Align the significands, d) None of the mentioned BSA X: X is memory location, need : b) 3 steps and 5 c) 3 steps and 3 a) 5 steps and 5 μ operations d) 5 steps and 3 μ operations u operations u operations
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