(1 point)Given that the Moon orbits the Earth every 27.3 days, and also the average distance from the Earth is found in Appendix C in Urone, then from applyingone of Kepier's Laws what is the period of a satellite orbiting at an average altitude of 1400 km above the Earth's surface? Include units as appropriate.T =

The time period of revolution of Moon, T1=27.3 d×24 hr1d=655.2 hr The distance of the Moon from the…

Answered: Given that the Moon orbits the Earth…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Question

(1 point)
Given that the Moon orbits the Earth every 27.3 days, and also the average distance from the Earth is found in Appendix C in Urone, then from applying
one of Kepier's Laws what is the period of a satellite orbiting at an average altitude of 1400 km above the Earth's surface? Include units as appropriate.
T =

Expert Solution

Given Data:

The time period of revolution of Moon, $T_{1} = 27.3 d \times \frac{24 hr}{1 d} = 655.2 hr$

The distance of the Moon from the Earth, $r_{1} = 3.84 \times 10^{5} km$

The altitude of the satellite from the surface of the Earth $= 1400 km$

Step 1

The time period of the satellite orbiting the earth will be given by third law of Kepler's laws of planetary motion.

The expression for third law of Kepler's laws of planetary motion is,

$\frac{{T_{1}}^{2}}{{T_{2}}^{2}} = \frac{{r_{1}}^{3}}{{r_{2}}^{3}}$

Here T₁ is the time period of first satellite and r₁ is the time period of that satellite and T₂ is the time period of second satellite and r₂ is the time period of that satellite. Both satellites should be orbiting around same celestial body.

The satellite is 1400 km above the surface, then the total distance from the center of the earth will be,

$r_{1} = radius of earth + 1400 km r_{1} = 6380 km + 1400 km r_{1} = 7780 km$

Step by step

Solved in 3 steps

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions