Given sinx== O O O O 161 289 225 289 161 289 225 289 15 and cos x > 0, what is the exact solution of cos 2x? 17

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Given \(\sin x = -\frac{15}{17}\) and \(\cos x > 0\), what is the exact solution of \(\cos 2x\)?

**Options:**

- A) \(\frac{161}{289}\)

- B) \(\frac{225}{289}\)

- C) \(-\frac{161}{289}\)

- D) \(-\frac{225}{289}\)

This problem requires the calculation of the double angle of cosine, \(\cos 2x\), given specific trigonometric conditions. Choose the correct solution from the provided options.
Transcribed Image Text:**Problem Statement:** Given \(\sin x = -\frac{15}{17}\) and \(\cos x > 0\), what is the exact solution of \(\cos 2x\)? **Options:** - A) \(\frac{161}{289}\) - B) \(\frac{225}{289}\) - C) \(-\frac{161}{289}\) - D) \(-\frac{225}{289}\) This problem requires the calculation of the double angle of cosine, \(\cos 2x\), given specific trigonometric conditions. Choose the correct solution from the provided options.
Expert Solution
Step 1

As we know that cosx=±1-sin2x

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