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Given: gm1 and gm2= 0.39 mS Rs=7.5k RL=100k CM=100pF CL=10nF Given transfer function: Vo(s) V:(s) - 9m gm, Im (CMCL) (1+ Rs gmi) CLRL S+ S+ gm² Cm 1.) Given the transfer function above, substitute the values and determine the location of the pole and zero frequencies. 2.) Determine the gain at DC, the pole, and zero frequencies. (The gain is in dB) 3.) Draw the Bode magnitude and phase plots. |

Given: gm1 and gm2= 0.39 mS Rs=7.5k RL=100k CM=100pF CL=10nF Given transfer function: Vo(s) V:(s) - 9m gm, Im (CMCL) (1+ Rs gmi) CLRL S+ S+ gm² Cm 1.) Given the transfer function above, substitute the values and determine the location of the pole and zero frequencies. 2.) Determine the gain at DC, the pole, and zero frequencies. (The gain is in dB) 3.) Draw the Bode magnitude and phase plots. |

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Note: The poles are posisitve. Please draw the plots by hand.

Given: gm1 and gm2= 0.39 mS Rs=7.5k RL=100k CM=100pF CL=10nF Given transfer function: Vo(s) Vi(s) gm, gmz mi (CmL) (1+ Rs gmi) CLR.) (5 S+ S+ gm² ст 1.) Given the transfer function above, substitute the values and determine the location of the pole and zero frequencies. 2.) Determine the gain at DC, the pole, and zero frequencies. (The gain is in dB) 3.) Draw the Bode magnitude and phase plots.
Transcribed Image Text:Given: gm1 and gm2= 0.39 mS Rs=7.5k RL=100k CM=100pF CL=10nF Given transfer function: Vo(s) Vi(s) gm, gmz mi (CmL) (1+ Rs gmi) CLR.) (5 S+ S+ gm² ст 1.) Given the transfer function above, substitute the values and determine the location of the pole and zero frequencies. 2.) Determine the gain at DC, the pole, and zero frequencies. (The gain is in dB) 3.) Draw the Bode magnitude and phase plots.
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could you  also solve for the gain at DC, and the two poles?

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