For the Theoretical SystemsWe could also calculate what values we SHOULD get from theoretical tables.The standard molar enthalpy of formation of CuSO4 is -771.4 kl/mol. The others can be found on the table T1, copiedbelow for Cu, Fe, Mg, and Zn.A= Mg + ZnS04 reacted to give MgSO4 + ZnReaction A = -1284.9 kJ/mol for MgSO4 formation (Zn is zero)+982.8 kl/mol for the destruction of ZNSO4 (Mg = 0)Similarly Reaction B is Zn + CUSO4 gives Cu + ZnSO4- 982.8 kJ/mol for the formation of ZnSO4 (Cu = 0)• 771.4 kJ/mol (for the destruction of CuS04)Overall for this reaction we should get a net heat RELEASE of -1284.9 + 771.4 = -513 kJ/molThis is because, as you can see, the ZnSO4 destroyed (reacted) in the first reaction is formed in the second, so these twowill cancel out, therefore giving the same theoretical result as the reaction of Mg and CuSO4.TRUE or FALSE- the experimental values are the same as the theoretical ones.Select onerTrueFalseCheckere to deatch

Given that, For Reaction A, Mg+ZnSO4 → MgSO4+Zn Reaction A =-1284.9 kJ/mol (MgSO4 formation)+982.8…

For the Theoretical Systems We could also calculate what values we SHOULD get from theoretical tables. The standard molar enthalpy of formation of CuSO4 is -771.4 kj/mol. The others can be found on the table T1, copied below for Cu, Fe, Mg, and Zn. A = Mg + ZnS04 reacted to give MgSO4 + Zn Reaction A = -1284.9 kJ/mol for MBSO4 formation (Zn is zero) + 982.8 kJ/mol for the destruction of ZnSO4 (Mg 0) Similarly Reaction B is Zn + CuSO4 gives Cu + ZnSO4 = - 982.8 kJ/mol for the formation of ZnS04 (Cu = 0) • 771.4 kJ/mol (for the destruction of CuS04) Overall for this reaction we should get a net heat RELEASE of -1284.9 + 771.4 = -513 kJ/mol This is because, as you can see, the ZnSO4 destroyed (reacted) in the first reaction is formed in the second, so these two will cancel out, therefore giving the same theoretical result as the reaction of Mg and CuSO4. TRUE or FALSE - the experimental values are the same as the theoretical ones. Select one: O True O False

For the Theoretical Systems We could also calculate what values we SHOULD get from theoretical tables. The standard molar enthalpy of formation of CuSO4 is -771.4 kj/mol. The others can be found on the table T1, copied below for Cu, Fe, Mg, and Zn. A = Mg + ZnS04 reacted to give MgSO4 + Zn Reaction A = -1284.9 kJ/mol for MBSO4 formation (Zn is zero) + 982.8 kJ/mol for the destruction of ZnSO4 (Mg 0) Similarly Reaction B is Zn + CuSO4 gives Cu + ZnSO4 = - 982.8 kJ/mol for the formation of ZnS04 (Cu = 0) • 771.4 kJ/mol (for the destruction of CuS04) Overall for this reaction we should get a net heat RELEASE of -1284.9 + 771.4 = -513 kJ/mol This is because, as you can see, the ZnSO4 destroyed (reacted) in the first reaction is formed in the second, so these two will cancel out, therefore giving the same theoretical result as the reaction of Mg and CuSO4. TRUE or FALSE - the experimental values are the same as the theoretical ones. Select one: O True O False

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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8.2
MN.19.
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