For a distribution the mean is 10, variance is 16, y, is +1 and B, = 4. Obtain the first four raw moments.
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- a standardize exam scores are normally distributed,in a recent year,the mean test scores was 1490,standard deviation was 320,the test sscores four for studentselected at a random are;1940,1249,and 1380.Find the Zscores that correspond to each vale and determine whether any of the values are unusualFor a certain type of computers, the length of time between charges of the battery is normally distributed with a mean of 62 hours and a standard deviation of 11 hours. John owns one of these computers and wants to know the number of hours when the computer would have 12% of its battery life left. Sketch the region in question. Write a sentence describing what your answer represents about the problem's specefics.A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1544 and the standard deviation was 314.The test scores of four students selected at random are 1940, 1290, 2250,and 1420.Find the z-scores that correspond to each value and determine whether any of the values are unusual. (Round to 2 decimal places as needed.)
- Q6/ Calculate mean, variance and standard deviation of following table: classes frequency 1-10 11 10-20 29 20-30 18 30-40 4 40-50 50-60 3The mean of the distribution of sample means would be equal to:The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do twenty year-olds have fewer cavities? The data show the results of a survey of 15 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 3, 4, 4, 4, 5, 5, 6, 4, 5, 4, 3, 5, 6, 5, 3 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v|| Select an answer H: ?v Select an answer v c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly less than 5 at o =- 0.05, so there is sufficient evidence to conclude that the population mean number of cavities for…
- Help fast pleasetimes for a surgical procedure are normally distributed. there are two methods. method a has a mean of 29 minutes and a standard deviation of 5 minutes, while method b has a mean of 33 minutes and a standard deviation of 25 minutes. which procedure is preferred if the procedure must be completed within 37 minutes. method a, b, or either methodThe average number of cavities that thirty-year-old Americans have had in their lifetimes is 7. Do twenty-year-olds have a different number of cavities? The data show the results of a survey of 13 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 9, 8, 8, 10, 10, 9, 9, 10, 6, 6, 9, 8, 8 What can be concluded at the α = 0.01 level of significance? The p-value = _______ (Please show your answer to 4 decimal places.) The p-value is _______ α Based on this, we should _________ the null hypothesis.
- he average amount of time boys and girls spend playing sports each week is believed to be the same. A sample of equal size n is taken from boys and girls , the mean of the boys is 29 hours with standard deviation 4 hours and the mean of the girls is 27 hours with standard deviation 3 hours Both populations have a normal distribution. The calculated value is 1.2 n =Exam scores in a large class are normally distributed with a mean of 55 and standard deviation of 10. The teacher decides to boost the scores by adding 20 points to everyone’s score. Elizabeth’s original score on the exam was 75, so her new score is 95. The z-score corresponding to her new score (relative to the other new scores) will be:If we meet these conditions, the sampling distribution of the mean will have a normal shape and ... The mean of the sampling distribution will be u, (i.e., the same as the population mean) and the standard deviation of the sampling distribution will be (that's the population standard deviation divided by the square root of the sample size). In the AP Stats Guy video, he talks about the number of text messages his students send during class. Suppose the average number of text messages his students send during class is u = 30 text messages. If we take samples of say, n = 36 students at a time, we would expect the mean of the sampling distribution we create to be the same as the population mean, 30 text messages. If we can further say that standard deviation of the number of text messages is 12 text messages, by how much would we expect the sample means to vary? (hint, use the formula above) text messages
