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f: R→R, and f(x) = 2x - 5 Select the correct statement about the inverse of f. O f-¹(x) = (x+5)/2 f-¹(x) = (x - 5)/2 f-¹(x) = 2(x - 5) f does not have a well-defined inverse.

f: R→R, and f(x) = 2x - 5 Select the correct statement about the inverse of f. O f-¹(x) = (x+5)/2 f-¹(x) = (x - 5)/2 f-¹(x) = 2(x - 5) f does not have a well-defined inverse.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The image contains a mathematical problem about finding the inverse of a function. The function is defined as follows: \( f : \mathbb{R} \rightarrow \mathbb{R}, \text{and} \ f(x) = 2x - 5 \) The problem statement asks to select the correct statement about the inverse of \( f \). There are several options provided: 1. \( f^{-1}(x) = \frac{(x + 5)}{2} \) 2. \( f^{-1}(x) = \frac{(x - 5)}{2} \) 3. \( f^{-1}(x) = 2(x - 5) \) 4. \( f \text{ does not have a well-defined inverse.} \)
Transcribed Image Text:The image contains a mathematical problem about finding the inverse of a function. The function is defined as follows: \( f : \mathbb{R} \rightarrow \mathbb{R}, \text{and} \ f(x) = 2x - 5 \) The problem statement asks to select the correct statement about the inverse of \( f \). There are several options provided: 1. \( f^{-1}(x) = \frac{(x + 5)}{2} \) 2. \( f^{-1}(x) = \frac{(x - 5)}{2} \) 3. \( f^{-1}(x) = 2(x - 5) \) 4. \( f \text{ does not have a well-defined inverse.} \)
### Question: Select the value that is equal to \(\lfloor \log_2 29 \rfloor\). - ○ 2 - ○ 3 - ○ 4 - ○ 5 ### Explanation: The floor function \(\lfloor x \rfloor\) denotes the greatest integer less than or equal to \(x\). To solve for \(\lfloor \log_2 29 \rfloor\), you must determine the largest integer \(n\) such that \(2^n \leq 29\). Logically, since \(2^4 = 16\) and \(2^5 = 32\), it's clear that \(4 < \log_2 29 < 5\). Thus, the greatest integer less than \(\log_2 29\) is 4. ### Correct Answer: - ○ 4
Transcribed Image Text:### Question: Select the value that is equal to \(\lfloor \log_2 29 \rfloor\). - ○ 2 - ○ 3 - ○ 4 - ○ 5 ### Explanation: The floor function \(\lfloor x \rfloor\) denotes the greatest integer less than or equal to \(x\). To solve for \(\lfloor \log_2 29 \rfloor\), you must determine the largest integer \(n\) such that \(2^n \leq 29\). Logically, since \(2^4 = 16\) and \(2^5 = 32\), it's clear that \(4 < \log_2 29 < 5\). Thus, the greatest integer less than \(\log_2 29\) is 4. ### Correct Answer: - ○ 4
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