e) Calculate the potential (vs. Ag | AgCI) when 10.8 mL of titrant is added. E = ) Calculate the potential (vs. Ag | AgCI) at the equivalence point. E = 3) Calculate the potential (vs. Ag|AgCI) when 19.2 mL of titrant is added. E = V

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A 36.0 mL solution of 0.0150 M Rh3+ in 1 M HClO4 was titrated with 0.0900 M Ce4+ to give Rh6+ and Ce3+. The reference electrode used is silver-silver chloride in saturated KCl.

e) Calculate the potential (vs. Ag | AgCI) when 10.8 mL of titrant is added.
E =
V
f) Calculate the potential (vs. Ag | AGCI) at the equivalence point.
E =
V
g) Calculate the potential (vs. Ag | AgCl) when 19.2 mL of titrant is added.
E =
V
h) At what volume of titrant will the potential be equal to the standard potential of the Ce half-reaction (ignoring the Ag | AgCl electrode)?
V =
mL
Transcribed Image Text:e) Calculate the potential (vs. Ag | AgCI) when 10.8 mL of titrant is added. E = V f) Calculate the potential (vs. Ag | AGCI) at the equivalence point. E = V g) Calculate the potential (vs. Ag | AgCl) when 19.2 mL of titrant is added. E = V h) At what volume of titrant will the potential be equal to the standard potential of the Ce half-reaction (ignoring the Ag | AgCl electrode)? V = mL
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