Disintegration Alpha. Explain what it's being used. The 238Pu decays by emission α according to the reaction: 238Pu → 234U + α + 5.49MeV with a period of 128 years. Being that of the 234U of 2.5 × 105 years. Estimate the initial mass of 238Pu needed to supply a minimum of 1kW of heat when 50 years have passed.
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- B1(a) In addition to uranium, plutonium is also a well-suited starting product for the release of energy through nuclear fission. If you bombard a ²32Pu nucleus with a neutron the fission products 94 barium ¹Ba and strontium 3Sr are formed. 56 (i) Write down the full equation of the reaction. (ii) Calculate the reaction energy in eV units. Note that m(232Pu) = 239.052162u, 94 m(¹Ba) = 143.922955u, and m(Sr) = 93.915356u. (iii) Explain what triggers a chain reaction with 232 Pu. 94Please answer this within 30 mins ! I will upvote !
- 1) Complete the reaction: 242Am + ? n → 90Sr + 149La + 4n a) n b) 2n c) 3n d) 4n e) 5n 2) Calculate the energy (in MeV) released in the nuclear fission reaction. The atomic masses are 242Am = 242.059549 u, 90Sr = 89.9077387 u, and 149La = 148.934733 u. (Express your answer to six significant figures).An atom of 239Pu decays into 235U and an alpha particle. How much energy (in MeV) is released due to the decay?b) 232U decays to 234Th by a emission. The decay t₁ = 4.47 × 10⁹ years. 92 2 i) Calculate the decay constant, λ. ii) If 30 g lump of 238U existed about 4.54 × 10º years ago when the earth was formed. Find the amount of 238U would be now. iii) Determine the number of a particle emitted per second it would currently emit.
- 28 23Al decays to 28Si via ß- emission with Tmax 2.865 MeV. 28Si is in 13 14' 14' the excited state which in turn decays to the ground state via y-emission. Find the y-ray energy. Take the masses 28 Al = 27.981908 amu, 28 Si 27.976929 amu.A beam of 8.47-MeV protons is incident on a target of 27/13 Al. Those protons that collide produce the reaction shown below. p + 27 13 Al → 27 14 Si + n ( 27 14 Si has a mass of 26.986721 u.) Neglecting any recoil of the product nucleus, determine the kinetic energy of the emerging neutrons. Answer:_____MeV Sorry the formatting is kinda off, im not sure how to fix it. Thank you!Consider the following decay: 209 83 Bi->> 205 TI + α. 81 209 Bi has a mass of 208.9803987 u, 205 TI has a mass of 204.9744275 u, and a has a mass of 4.002603 u. 81 83 A.) Determine the disintegration energy (Q-value) in MeV. Q= B.) Determine the KE of the daughter in MeV. KED= C.) Determine the KE of the a particle in MeV & as a factor of Q. KE = KE=Qx D.) Determine the speed of the a particle in terms of c. For an a particle, E, = 3.727 GeV. [NOTE: G stands for giga- which means 109 &M stands for mega- which means 106.] XC
- 3. the value of Q from the following decay: Calculate π a. →μ +V b. π →γ+γ πο c. K >π επ d. Σ* →p+7° Σ° +1° +γ e.Determine the number of protons in the missing fragment of the reaction shown below: In+25U ?+135 Xe + 12n+ 126.5 MeV 54 Express your answer as an integer. Temptates Symbols undo rego Teset keyboard shortcuts tlelp Z =226 24°Ra nucleus decays to 22"Rn nucleus by a radiation. How much energy is released during this process? What is the kinetic energy of the released a particle? How big is the recoil energy of the 22"Rn nucleus? (1 u 931.494 MeV/c, the needed mass = values are He:4.002603 u, Rn:222.017570 u, Ra:226.025402 u)