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Consider the following values in the given beam above: L1-6m L2=2m L3=4m L4=3m L5=2m L6=1 m W1 90 kN/m W2-30 kN/m P-50 KN M-60 kN-m Point E is an internal hinge L1 W1 B L2 C L3 2m E W2 L4 L5 M L6 H

Consider the following values in the given beam above: L1-6m L2=2m L3=4m L4=3m L5=2m L6=1 m W1 90 kN/m W2-30 kN/m P-50 KN M-60 kN-m Point E is an internal hinge L1 W1 B L2 C L3 2m E W2 L4 L5 M L6 H

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The maximum positive moment at segment AC is The maximum positive moment at segment CF is The maximum shear along the entire span of the beam is The maximum positive moment along the entire span of the beam is The maximum negative moment along the entire span of the beam is kN-m. It is located at kN-m. kN. kN-m. kN-m. m from point A. Express all your answers in three decimal places. For the reactions, there is NO NEED to put the sign. For V and M values, ALWAYS include the sign (+ or -) to denote the nature of shear and bending. Not indicating the sign will mark your answer wrong. No considerations.
Transcribed Image Text:The maximum positive moment at segment AC is The maximum positive moment at segment CF is The maximum shear along the entire span of the beam is The maximum positive moment along the entire span of the beam is The maximum negative moment along the entire span of the beam is kN-m. It is located at kN-m. kN. kN-m. kN-m. m from point A. Express all your answers in three decimal places. For the reactions, there is NO NEED to put the sign. For V and M values, ALWAYS include the sign (+ or -) to denote the nature of shear and bending. Not indicating the sign will mark your answer wrong. No considerations.
Consider the following values in the given beam above: L1=6m L2 = 2 m L3 = 4 m L4=3m L5=2 m L6=1m W1 = 90 kN/m W2 = 30 kN/m P = 50 kN M = 60 kN-m Point E is an internal hinge W1 B L2 L3 2 m E W2 L5 L6 H
Transcribed Image Text:Consider the following values in the given beam above: L1=6m L2 = 2 m L3 = 4 m L4=3m L5=2 m L6=1m W1 = 90 kN/m W2 = 30 kN/m P = 50 kN M = 60 kN-m Point E is an internal hinge W1 B L2 L3 2 m E W2 L5 L6 H
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