Consider the following (true) claim and two possible proofs. Claim. If n is a positive integer, then n² + 3n+2 is not a prime number. Proof 1. Note that n² + 3n+ 2 = (n + 2)(n+1). Since n ≥ 1, we have n+1>1 and n+2 > 1, so n²+3n+2 has at least two divisors other than 1 and is therefore not prime.
Consider the following (true) claim and two possible proofs. Claim. If n is a positive integer, then n² + 3n+2 is not a prime number. Proof 1. Note that n² + 3n+ 2 = (n + 2)(n+1). Since n ≥ 1, we have n+1>1 and n+2 > 1, so n²+3n+2 has at least two divisors other than 1 and is therefore not prime.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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![12. Consider the following (true) claim and two possible proofs.
Claim. If n is a positive integer, then n² + 3n+2 is not a prime number.
Proof 1. Note that n² + 3n+2= (n + 2)(n+1). Since n 1, we have n + 1 > 1 and
n+2 > 1, so n²+3n+2 has at least two divisors other than 1 and is therefore not prime.
Proof 2. If n is even then we can write n = 2k for some positive integer k. Then
n² + 3n+2 = 4k² +6k+2 = 2(2k² +3k+1), which is even and greater than 2. Since 2
is the only even prime, it follows that n² + 3n+2 is not prime.
Which of these proofs are valid (i.e. which of them actually prove the claim)?
(a) Both proofs are valid.
(b) Proof 1 is valid, but Proof 2 is not.
(c) Proof 2 is valid, but Proof 1 is not.
(d) Neither proof is valid.
Select one alternative:
(a)
(b)
O (c)
O (d)
[1 mark]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fda0be02e-f777-40ec-8b6c-8836435acb5a%2F1dba3763-ac8c-44c6-a8c4-7facd2f7991d%2Fojthbi_processed.png&w=3840&q=75)
Transcribed Image Text:12. Consider the following (true) claim and two possible proofs.
Claim. If n is a positive integer, then n² + 3n+2 is not a prime number.
Proof 1. Note that n² + 3n+2= (n + 2)(n+1). Since n 1, we have n + 1 > 1 and
n+2 > 1, so n²+3n+2 has at least two divisors other than 1 and is therefore not prime.
Proof 2. If n is even then we can write n = 2k for some positive integer k. Then
n² + 3n+2 = 4k² +6k+2 = 2(2k² +3k+1), which is even and greater than 2. Since 2
is the only even prime, it follows that n² + 3n+2 is not prime.
Which of these proofs are valid (i.e. which of them actually prove the claim)?
(a) Both proofs are valid.
(b) Proof 1 is valid, but Proof 2 is not.
(c) Proof 2 is valid, but Proof 1 is not.
(d) Neither proof is valid.
Select one alternative:
(a)
(b)
O (c)
O (d)
[1 mark]
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