Consider the following estimated regression equation, based on 10 observations. ŷ = 29.1270 +0.5906x1 +0.4980x2 The values of SST and SSR are 6,724.125 and 6,216.375, respectively. a. Find SSE (to 2 decimals). b. Compute R² (to 3 decimals). c. Compute R (to 3 decimals).
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A: From the given information, y=a+bxb=-0.79a=23.38 Therefore, Y=23.38-0.79X
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A: Givena=-0.816b=24.08r2=0.494209r=-0.703y=ax+b
Q: Given the following multiple regression equation : y = 122+ 2 x + 1x2, where Y:Total expenses, X:…
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Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: given data here, x=no of hour tv watched per day. y=number of Situps a person Can do. a=-1.13…
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
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Q: A regression was run to determine if there is a relationship between hours of TV watched per day…
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Q: (b) Predict y when x₁ = 10, X₂ = 5, X3 = 1, and x4 = 2. X
A: Here: Given regression equation is y^=17.9+3.1X1-2.5X2+7.8X3+2.7X4 We have to interpret b1,b2,b3,b4…
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: Given results: The regression line : y =-0.904x+39.953
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Q: The following estimated regression equation based on 10 observations was presented. ŷ 29.1290 +…
A: Step 1: GivenNumber of observations, N=10Number of independent variables,…
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: Regression Analysis y = ax+b given , a = -1.235 b =37.403 Put x = 9 in regression equation y =…
Q: The following estimated regression equation based on 10 observations was presented. ý = 29.1270 +…
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Q: A regression analysis was performed to determine if there is a relationship between hours of TV…
A: Given that the regression equation is, y=ax+b b=31.768 a=-1.128 Therefore, y=-1.128x+31.768
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Q: The following estimated regression equation based on 10 observations was presented. ŷ 29.1210+…
A: n=10, k=number of explanatory variables=2, SST=6717.125, SSR=6213.375
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: The results of the regression were: y=ax+b a=-0.788 b=22.872 r2=0.388129 r=-0.623
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: Solution: It is given here:
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: Solution: Let X be the number of hours of TV watched per day and Y be the number of sit-ups a person…
Q: regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: Slope (a)=-0.709 Intercept (b)=36.701 Then,linear regression equation is y=-0.709x +36.701
Q: In a regression analysis involving 30 observations, the following estimated regression equation was…
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Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: Solution: The estimated regression equation is y^=-1.262x+26.502
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: The given regression line is: y=-1.086x+21.604
Q: A regression analysis was performed to determine if there is a relationship between hours of TV…
A: y = ax+b = -1.223x+22.907
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: It is given that, Slope, a =-0.849 Intercept,b =32.064 Thus, the regression line is : y…
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (X)…
A: Given - A Regression was run to determine if there is a relationship between hours of TV watched per…
Q: A regression analysis was performed to determine if there is a relationship between hours of TV…
A: It is given that the value of a is –1.152 and b is 30.418.
Q: The following estimated regression equation based on 10 observations was presented. ý = 29.1270 +…
A: Given :n = 10
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Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: The regression equation is y = 28.724 – 1.299x, where x is the hours of TV watched per day and y is…
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A: Given Data: Let us consider the given regression equation: Yi^=4.37+0.2X1i+0.3X2i
Q: The following estimated regression equation based on 10 observations was presented. ŷ = 29.1260 +…
A: Hello! As you have posted 4 sub parts, we are answering the first 3 sub-parts. In case you require…
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Q: The following estimated regression equation is based on 10 observations was presented. ŷ = 29.1270 +…
A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: Compute R2. (Round your answer to thre R2 = Compute R. (Round your answer to thr Comment on the…
A: Total sum of squares, SST = 1803 Sum of squares of regression, SSR = 1756 Number of observations, n…
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A: Given : The regression Line Here coefficient of x values : b1 = 3.7b2 = -2.2b3 = 7.9b4 = 2.6…
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A: We have given a regression equation and we have to predict the value of y for x=11.5
Q: A regression was run to determine if there is a relationship between hours of TV watched per day (x)…
A: We have given that , Y=ax+b Where, a=-1.003 ,b=29.085, at x=6 hours
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- Consider the regression équation In =3.94+0.4X₁₁ +0.7X₂- a. Predict the value of Y when X₁ =7.4 and X₂ = 5.2. b. Interpret the meaning of the regression coefficients 100 b,, and 100-b₂. a. The predicted value of Y is (Type an integer or decimal rounded to two decimal places as needed.) b. Choose the correct answer below. OA. Holding constant the other variables, for every one unit increase in X, or X₂, the value of Y increases by b, or by percent, respectively. B. Holding constant the other variables, for every one percent increase in X, or X₂, the value of Y increases by b, or b₂ percent, respectively. C. Holding constant the other variables, for every one unit increase in X, or X₂, the value of Y increases by 100 b, or 100-b₂ percent, respectively. OD. Holding constant the other variables, for every one percent increase in X, or X₂, the value of Y increases by b, or b₂ units, respectively. OE. For every decrease of one unit of In Y, holding bo constant, the estimated change in X, or…A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.307 b=32.392 r²=0.675684 r=-0.822 Use this to predict the number of situps a person who watches 12.5 hours of TV can do (to one decimal place)Interpret the intercept and the coefficients of D1 and D2 in the regression above.
- Data from 147 colleges from 1995 to 2005 (Lee,2008) were tested to predict the endowments (in billions) to a college from the average SAT score of students attending the college. The resulting regression equation was Y = -20.46 + 4.06 (X). This regression indicates that: a. for every one-point increase in SAT scores, a college can expect 4.06 billion more in endowments. b. most colleges have very high endowments. c. for every one-point increase in SAT scores, a college can expect 20.46 billion fewer in endowments. d. for every one-dollar increase in endowments, the college can expect a half-point increase in SAT scores.A researcher is interested in finding out the factors which determined the yearly spending on family outings last year (Y, measured in dollars). She compiles data on the number of members in a family (X1), the annual income of the family (X2), and the number of times the family went out on an outing in the last year (X3). She collects data from 196 families and estimates the following regression: Y=120.45+1.54X1+2.12X2+2.12X3. Suppose β1, β2, β3, denote the population slope coefficients of X1, X2, and X3, respectively. The researcher wants to check if neither X1 nor X2 have a significant effect on Y or at least one of them has a significant effect, keeping X3 constant. She calculates the value of the F-statistic for the test with the two restrictions (H0: β1=0, β2=0 vs. H1: β1≠0 and/or β2≠0) to be 3.00. The p-value for the test will be enter your response here?A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-0.971 b=21.794 r²-0.872356 r=-0.934 Use this to predict the number of situps a person who watches 5 hours of TV can do (to one decimal place)
- A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were:y=ax+b a=-0.982 b=31.084 r2=0.471969 r=-0.687 Use this to predict the number of situps a person who watches 13.5 hours of TV can do (to one decimal place)The following estimated regression equation based on 10 observations was presented. ŷ= 29.1230+ 0.5806x + 0.4380x2 The values of SST and SSR are 6,725.125 and 6,223.375, respectively. (a) Find SSE. SSE= (b) Compute R2. (Round your answer to three decimal places.) R² = (c) Compute R. (Round your answer to three decimal places.) R2= (d) Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) O The estimated regression equation did not provide a good fit as a large proportion of the variability in y has been explained by the estimated regression equation. O The estimated regression equation did not provide a good fit as a small proportion of the variability in y has been explained by the estimated regression equation. O The estimated regression equation provided a good fit as a large proportion of the variability in y has been explained by the estimated regression equation. O The estimated regression equation provided a good fit…A regression was run to determine if there is a relationship between hours of TV watched per day (x) and the number of sit-ups a person can do (y). The results were: Y a+bx b = -0.79 = 23.04 a r² = 0.4493 r = -0.6703 a. If a person watches 10 hours of television a day, predict how many sit-ups he can do. b. If a person can do 7 sit ups, predict how many hours of television a day they watch. hours
- a. What is the probability of seeing positive change? b. What is the probability of seeing positive change given that the tree is oak? c. Do the data suggest effect and tree type are independent events? yes or noA regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were:y=ax+b a=-1.34 b=36.954 r2=0.966289 r=-0.983 Use this to predict the number of situps a person who watches 5 hours of TV can do (to one decimal place)Use the following linear regression equation to answer the questions. x1 = 1.0 + 3.9x2 – 8.4x3 + 2.4x4 Suppose x2 decreased by 4 units. What would be the expected change in x1?