Consider a simple spring mass damper system with m=55x10A-3 kg, c = 0.12 kg/s, and k = 859 N/m. Calculate thevalue of the steady state response if w = 120 rad/s and fo- 12 N/kg.O A Damping ratio = 0.00973Natural frequency = 114.97 rad/sAmplitude displacement for Steady state response(X) = 0.00864 mDamping ratio = 0.00773Natural frequency = 134.97 rad/sAmplitude displacement for Steady state response(X) = 0.01964 mO C. Damping ratio = 0.00873Natural frequency = 124.97 rad/sAmplitude displacement for Steady state response(x) = 0.00964 m

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Consider a simple spring mass damper system with m= 55X10A-3 kg, c- 0.12 kg/s, and k = 859 N/m. Calculate the value of the steady state response if w - 120 rad/s and to - 12 N/kg O A Natural frequency = 114.97 rad/s Damping ratio = 0.00973 Amplitude displacement for Steady state response (X) = 0.00864 m B. Damping ratio - 0.00773 Natural frequency 134.97 rad/s Amplitude displacement for Steady state response (X) 0.01964 m OC. Damping ratio - 0.00873 Natural frequency 124.97 rad/s Amplitude displacement for Steady state response (x) - 0.00964 m

Consider a simple spring mass damper system with m= 55X10A-3 kg, c- 0.12 kg/s, and k = 859 N/m. Calculate the value of the steady state response if w - 120 rad/s and to - 12 N/kg O A Natural frequency = 114.97 rad/s Damping ratio = 0.00973 Amplitude displacement for Steady state response (X) = 0.00864 m B. Damping ratio - 0.00773 Natural frequency 134.97 rad/s Amplitude displacement for Steady state response (X) 0.01964 m OC. Damping ratio - 0.00873 Natural frequency 124.97 rad/s Amplitude displacement for Steady state response (x) - 0.00964 m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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