Answered: Consider a place where the gravity is… | bartleby

Related questions

Question

100%

Consider a place where the gravity is one-
fourth the gravity on Earth (g' = g/4), then
%3D
the frequency of oscillation of a simple
pendulum in that place, f', as compared to
its frequency on earth is:
O f' = 2f
O f' = 4f
O f' = f/3
f' = f/2
O f' = 9f

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A hole is drilled through the center of the earth. The gravitational force on a mass in that hole is mgr/R, where r is the distance of the mass from the earth’s center and R is the radius of the earth (6.4 x 10 6m).A mass dropped into the hole executes simple harmonic motion. Find the period of the motion. How does one-half this time compare with the time needed to fly in an air-’ plane halfway around the earth?
Consider a place where the gravity is one-fourth the gravity on Earth (g' = %3D g/4), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is:
A simple pendulum of length L and mass M has frequency f. To increase its frequency to 3f, increase its length to 3L O decrease its length to L/9 O increase its length to 9L O decrease its length to L/3 O None of the listed choices
The distance of a swinging pendulum from its resting position is given by the function dit) = 5.5cos(8), where the distance is in inchès and the time is in seconds. Once released, how long will it take the pendulum to reach its resting position? Round your answer to the nearest hundredth.
A newly discovered planet is found to have the acceleration due to gravity g = 6m / (s ^ 2) How much time would a simple pendulum of length 0.5 m take to make one complete swing on that planet?
Suppose the oscillatory motion of an object can be modeled using the equation s(t) = 0.5sin(0.21t) where time is measured in seconds and distance is measured in inches. Find the time (in seconds) required for the object to complete one oscillation. (Provide 4 decimal places.)
The acceleration due to gravity on Planet X is 0.360 times the acceleration on Earth. What length (in cm) of simple pendulum would have a period of 1.20 s on Planet X? Round your answer to 2 decimal places.