Complete the following reactions. Show the stereother DMF 411B+ + Na CN हुई CHS сиз сиз-енен СЊCRO С.Ненз Br Ea +C12/10 Perotidi NQ OH > MgBr ol. + HBr + pec + pels 6 CH-CH= снесия CH3 NBS +H2O heat H₂ crown NANH2 ничко ссия H₂ 504> Cl Си-ен- сна-ен-он Кмпой (сд re

Chemistry
10th Edition
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Complete the following reactions. Show the stereochemistry where applicable.
DMF
iBT + H₂ CN
CHS
сиз
си-ей антена сцена в
E2
Br
+cla/mo
perotide
: No OH >
H₂ Croutz
MgBr
애
+ HBr
+ pac
po
ой
+ pels
❤
CH-CH- снесия
стану
NBS
+H20
heat
H
NANH2
HH₂(1)
H₂ 504 >
Cl
Си-Ен= CH2-CH-он
Кмпой (G)
YL
Transcribed Image Text:Complete the following reactions. Show the stereochemistry where applicable. DMF iBT + H₂ CN CHS сиз си-ей антена сцена в E2 Br +cla/mo perotide : No OH > H₂ Croutz MgBr 애 + HBr + pac po ой + pels ❤ CH-CH- снесия стану NBS +H20 heat H NANH2 HH₂(1) H₂ 504 > Cl Си-Ен= CH2-CH-он Кмпой (G) YL
Identify the following pairs as enantiomers, diastereomers or meso compound or identical.
ÇHz
CH3
H-
Brim
M
Br
(IV) Show the reaction mechanism for the following conversion to give products A
and B. Use curved arrows properly to show the direction of electron flow.
CH3
#CH3
Sans + O
+ HCI
BOH
A
B
-BY
CM3
-H.
-BY
HB
¿H3
Slims
Transcribed Image Text:Identify the following pairs as enantiomers, diastereomers or meso compound or identical. ÇHz CH3 H- Brim M Br (IV) Show the reaction mechanism for the following conversion to give products A and B. Use curved arrows properly to show the direction of electron flow. CH3 #CH3 Sans + O + HCI BOH A B -BY CM3 -H. -BY HB ¿H3 Slims
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This last part didnt post! But I was wondering, for your #6, how do both cls leave?

Answer the following:
R₁
·X + Nu-
I[=+13.5⁰
II product with [x]=-8.4°
In the above reaction, optically active compound I has a specific rotation of +13.5°, and
compound II with a 100% enantiomeric excess exists with a specific rotation of +16.8° or
-16.8°. However, when compound II was prepared from I the specific rotation of
the product was - 8.4º,
a) Explain this observation in terms of the mechanism of the reaction. (Show the reaction
Mechanism)
b) Calculate the enantiomeric excees of the product
c) What is the percent composition of the product.
R₂-C-Nu
R3
Where: R₁ R2 R³ ‡X #Nu
Transcribed Image Text:Answer the following: R₁ ·X + Nu- I[=+13.5⁰ II product with [x]=-8.4° In the above reaction, optically active compound I has a specific rotation of +13.5°, and compound II with a 100% enantiomeric excess exists with a specific rotation of +16.8° or -16.8°. However, when compound II was prepared from I the specific rotation of the product was - 8.4º, a) Explain this observation in terms of the mechanism of the reaction. (Show the reaction Mechanism) b) Calculate the enantiomeric excees of the product c) What is the percent composition of the product. R₂-C-Nu R3 Where: R₁ R2 R³ ‡X #Nu
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