Chapter Eight 8.21- Consider two rectangular surfaces perpendicular to each other with a common edge which is 1.6m long. The horizontal surface is 0.8m wide and the vertical surface is 1.2m high. The horizontal surface has an emissivity of 0.75 and is maintained at 400K. The vertical surface is black and is maintained at 550K. The backsides of the surfaces are insulated. The surrounding surfaces are at 290K, and can be considered to have an emissivity of 0.85. Determine the net rate of radiation heat transfers between the two surfaces, and between the horizontal surface and the surroundings. Answer: 1245 W, 725 W Prob.(8.21) T₂ = 550 K &₂=1 L₂=1.2 m 1.2 m L₁=0.8 m W = 1.6 m A₂ 2 A₁ (1) T₁ = 400 K £₁ = 0.75 T3 = 290 K €3=0.85

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Chapter Eight
8.21- Consider two rectangular surfaces
perpendicular to each other with a common edge
which is 1.6m long. The horizontal surface is
0.8m wide and the vertical surface is 1.2m high.
The horizontal surface has an emissivity of 0.75
and is maintained at 400K. The vertical surface is
black and is maintained at 550K. The backsides
of the surfaces are insulated. The surrounding
surfaces are at 290K, and can be considered to
have an emissivity of 0.85. Determine the net rate
of radiation heat transfers between the two
surfaces, and between the horizontal surface and
the surroundings. Answer: 1245 W, 725 W
T₂ = 550 K
&₂=1
W = 1.6 m
(3)
L₂=1.2 m
A₂
T3 = 290 K
€3=0.85
A₁ (1)
Prob.(8.21)
L₁=0.8 m
T₁ = 400 K
£₁ = 0.75
Transcribed Image Text:Chapter Eight 8.21- Consider two rectangular surfaces perpendicular to each other with a common edge which is 1.6m long. The horizontal surface is 0.8m wide and the vertical surface is 1.2m high. The horizontal surface has an emissivity of 0.75 and is maintained at 400K. The vertical surface is black and is maintained at 550K. The backsides of the surfaces are insulated. The surrounding surfaces are at 290K, and can be considered to have an emissivity of 0.85. Determine the net rate of radiation heat transfers between the two surfaces, and between the horizontal surface and the surroundings. Answer: 1245 W, 725 W T₂ = 550 K &₂=1 W = 1.6 m (3) L₂=1.2 m A₂ T3 = 290 K €3=0.85 A₁ (1) Prob.(8.21) L₁=0.8 m T₁ = 400 K £₁ = 0.75
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