CD3 ÇH5 CD3 `C,H5 `CD3 C,H5 `CD3 100 °C CH3 C,H5 C,Hs CH, ČH3 ČH3 D A

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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If isomer A is heated to about 100 °C, a mixture of isomers A and B is formed. Explain why there is no trace of isomer C or D.

CD3
ÇH5
CD3
`C,H5
`CD3
C,H5
`CD3
100 °C
CH3
C,H5
C,Hs
CH,
ČH3
ČH3
D
A
Transcribed Image Text:CD3 ÇH5 CD3 `C,H5 `CD3 C,H5 `CD3 100 °C CH3 C,H5 C,Hs CH, ČH3 ČH3 D A
Expert Solution
Step 1

Isomer A is heated to about 100oC and mixture of isomers A and B are formed but there is no trace isomer C or D.The 

Step 2

The reason for this behavior can be explained as follows:

The reactant isomer A has two pi bonds. According to Woodward Hoffmann rules, electrocyclic ring closure is conrotatory. Due to this, the two different compounds namely X and Y can be formed because conrotatory ring closure can occur in either a clockwise or an anti-clockwise direction. This can be represented as follows:

Chemistry homework question answer, step 2, image 1

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