Calculate the quality of ammonia at state 2 using the relation, v; = (v; ), +x (va), 0.04 = 0.00168 +x, (0.10881) X, = 0.35217

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Calculate the quality of ammonia at state 2 using the relation,
v, = (v,), +x (Va),
0.04 = 0.00168 +x, (0.10881)
0.35217
The pressure remains constant during the process 1-2'.
temperature
Obtain
the
R= P, =1600kPaand
at
V, = v, = 0.04m / kg from saturated ammonia tables.
T = 41°C
The heat transfer takes place between the ammonia and steel is due
to the change in internal energy and change in specific volume
during the process.
The
process
from 1-2' is constant pressure and 2'-2 is the constant
volume process.
Draw the process on p-v diagram as shown.
P
Calculate the work done in the process 1 to 2.
W = W2 +Wy-2
= P(V, -V,)+0
=1600(0.02 – 0.05634)
%3D
W, =-58.144kJ
Negative sign indicates work done on the system.
Transcribed Image Text:Calculate the quality of ammonia at state 2 using the relation, v, = (v,), +x (Va), 0.04 = 0.00168 +x, (0.10881) 0.35217 The pressure remains constant during the process 1-2'. temperature Obtain the R= P, =1600kPaand at V, = v, = 0.04m / kg from saturated ammonia tables. T = 41°C The heat transfer takes place between the ammonia and steel is due to the change in internal energy and change in specific volume during the process. The process from 1-2' is constant pressure and 2'-2 is the constant volume process. Draw the process on p-v diagram as shown. P Calculate the work done in the process 1 to 2. W = W2 +Wy-2 = P(V, -V,)+0 =1600(0.02 – 0.05634) %3D W, =-58.144kJ Negative sign indicates work done on the system.
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