) Calculate the deBroglie wavelength of an electron with energy Ef in copper and b) compare it to the atomic separation in copper
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Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: Given data- λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: Given data- λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: Given data- λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
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Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: We know that- Given data- λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
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Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: Given data- h=6.63 × 10-34 J sc = 3 × 108 m/s.λ=400 nmE=?
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Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: We have data- λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: Given data- λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
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Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: We know that- λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
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Q: If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band…
A: We know that λ =400 nm c = 3 × 108 m/s h = 6.63 × 10–34 J.s
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