C++. Can you please explain the function call and how it works in this specific example. #include using namespace std;edouble addOne (double numberIn){double numberOut;numberOut = numberIn + 1;return numberOut;double original, modified;cout << "Enter a number: ";cin >> original;modified = addOne (original);cout << "Your number plus one is "return 0;}int main(){}Function definitionExecution starts here, even thoughthe other function is listed first.Function call<< modified <<"." << endl;

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C++. Can you please explain the function call and how it works in this specific example.

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Question

C++. Can you please explain the function call and how it works in this specific example.

#include <iostream>
using namespace std;
edouble addOne (double numberIn)
{
double numberOut;
numberOut = numberIn + 1;
return numberOut;
double original, modified;
cout << "Enter a number: ";
cin >> original;
modified = addOne (original);
cout << "Your number plus one is "
return 0;
}
int main()
{
}
Function definition
Execution starts here, even though
the other function is listed first.
Function call
<< modified <<
"." << endl;

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