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(c) A circuit connected to a practical source is shown in Figure 4.1. Determine (1) the voltage V₁ across a broken wire, (ii) (iii) the voltages V₂ and VL. the power dissipated in the internal resistance Rint. Practical R=592 source 1 25 V V₁ www R₁ = 102 Figure 4.1 R₁ = 102 ww R₁ = 150 R₂ = 252 V₁ (d) Referring to the network in Figure 4.2, use nodal analysis to find the voltage Va and the currents 11, 12 and 13. 1₁ 1052 8V I Ω 30 (2 ww V₂ Figure 4.2 40 Ω 12 50 V 1₂ 2002

(c) A circuit connected to a practical source is shown in Figure 4.1. Determine (1) the voltage V₁ across a broken wire, (ii) (iii) the voltages V₂ and VL. the power dissipated in the internal resistance Rint. Practical R=592 source 1 25 V V₁ www R₁ = 102 Figure 4.1 R₁ = 102 ww R₁ = 150 R₂ = 252 V₁ (d) Referring to the network in Figure 4.2, use nodal analysis to find the voltage Va and the currents 11, 12 and 13. 1₁ 1052 8V I Ω 30 (2 ww V₂ Figure 4.2 40 Ω 12 50 V 1₂ 2002

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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(c) A circuit connected to a practical source is shown in Figure 4.1. Determine (i) the voltage V₁ across a broken wire, (ii) the voltages V2 and VL, (iii) the power dissipated in the internal resistance Rint. Practical source R = 552 25 V V₁ V₂ www R₂ = 10 92 Figure 4.1 R₁ = 1092 ww R₁ = 152 R₂ = 252 V₁ (d) Referring to the network in Figure 4.2, use nodal analysis to find the voltage Va and the currents 11, 12 and 13. I₁ 1052 8V 30 Ω www V₂ Figure 4.2 40 Ω 50 V 13 20 Ω
Transcribed Image Text:(c) A circuit connected to a practical source is shown in Figure 4.1. Determine (i) the voltage V₁ across a broken wire, (ii) the voltages V2 and VL, (iii) the power dissipated in the internal resistance Rint. Practical source R = 552 25 V V₁ V₂ www R₂ = 10 92 Figure 4.1 R₁ = 1092 ww R₁ = 152 R₂ = 252 V₁ (d) Referring to the network in Figure 4.2, use nodal analysis to find the voltage Va and the currents 11, 12 and 13. I₁ 1052 8V 30 Ω www V₂ Figure 4.2 40 Ω 50 V 13 20 Ω
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