Bob selects independent random samples fromtwo populations and obtains the values pi0.700 and p2 = 0.500. He constructs the 95%confidence interval for p1 – P2 and gets:|0.200 ± 1.96(0.048) = 0.200 ±0.094.Note that 0.048 is called the estimated standarderror of ĝ1 – p2 (the ESE of the estimate).Tom wants to estimate the mean of the successrates:Pi + P22(a) Calculate Tom's point estimate.(b) Given that the estimated standard er-ror of (p1 + P2)/2 is 0.024, calculatethe 95% confidence interval estimate of(p1 + p2)/2. Hint: The answer has ourusual form:Pt. est. + 1.96 × ESE of the estimate.

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Answered: Bob selects independent random samples…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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es A sample of 12 fossil skeletons of an extinct species of bird has been collected. The mean length of the skulls in this sample is 5.29 cm and the standard deviation of the sample is 0.21 cm. Assuming that such measurements are normally distributed, find a 90% confidence interval for the population mean length of the skulls of this species of bird. You may want to use one of these: qt (p-0.10, df-11, lower. tail-FALSE)=1.36343 qt(p-0.05, df-11, lower.tail-FALSE) =1.795885 qnorm(0.10, mean-0, sd-1, lower.tail-FALSE)=1.281552 qnorm(0.05, mean-0, sd-1, lower.tail=FALSE)=1.644854 O (4.945, 5.635) O (4.913, 5.667) O (5.021, 5.559) O (5.181, 5.399)
In a sample of 12 randomly selected high school seniors, the mean score on a standardized test was 1182 and the standard deviation was 161.6.Further research suggests that the population mean score on this test for high school seniors is 1012. Does the t-value for the original sample fall between −t0.95 and t0.95? Assume that the population of test scores for high school seniors is normally distributed. What is The t-value? And does or does not it not fall between −t0.95 and t0.95 because t0.95=? (Round to two decimal places as needed.)
Q1: A researcher was interested in the effect of exercise on stress levels. For the general population, the distribution of the Stress Battery Scale scores is normal with the mean of µ = 25 and the standard deviation of σ = 5. A sample of n = 100 participants was asked to exercise for three weeks and then reported their stress levels. The sample mean was ?X = 23. Conduct a hypothesis test and determine the effect of exercise. Use the two-tailed test α = .01 1.Type the null and research hypotheses in complete sentences. 2.Cut off points 3.Standard error and z-score -show your computation process 4.Your conclusion thoroughly.
A sample of 200 people has a mean age of 21 with a population standard deviation (σ) of 5. Test the hypothesis that the population mean is 18.9 at α = 0.05.
Please answer this question for me because i do not understand how to work it.
A marketing researcher is hired by a corporation to conduct a study and estimate the population mean for the attribute of interest using a 98% confidence interval with a maximum error of 5. It will cost the researcher $15 per sample to conduct the study and the researcher has been given a budget of $750 to conduct the study. Based on prior studies the researcher can estimate the standard deviation using, σ≈16�≈16. Step 1 of 3: Calculate the minimum sample size needed for this study. Round your answer up to the nearest whole number.
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Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3,300. A random sample of 12 assisted-living facilities had an average rate of $3,690 per month. The standard deviation for this sample was $530. Medicare would like to set α = 0.02. The critical value for this hypothesis test would be

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