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b) ly. f x* 8(x, y)dA = f L*'dxdy %3D 12 Multiple Integral (1,1) 12y-y2 = H dy = (2y- y*) -y*ldy =(8y* - 12y* + 6ys – y6 - y")dy =8y* - 12y + 6ys - 2y) dy =(ay - 6y* + 3y - y)dy 3x11 11 Ry 105 35 H.W. Find l, ly,Ry and Ry

b) ly. f x* 8(x, y)dA = f L*'dxdy %3D 12 Multiple Integral (1,1) 12y-y2 = H dy = (2y- y*) -y*ldy =(8y* - 12y* + 6ys – y6 - y")dy =8y* - 12y + 6ys - 2y) dy =(ay - 6y* + 3y - y)dy 3x11 11 Ry 105 35 H.W. Find l, ly,Ry and Ry

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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78 l all ? 2_52606602927270... 2 Jo L b) ly- f x* 8(x, y)dA = S, " x?dxdy 12 Multiple Integral (1,1) = H dy =(2y- y*)" - y^) dy = (8y - 12y +6ys - y - y")dy =, (8y* - 12y* + 6y - 2y) dy =(4y - 6y* + 3y5- y)dy -厚 3x11 V 105 Ry = %3D H.W. Find l, ly,Ry and Ry Integration in Polar Coordinates: To find the integral of a function f(x, y) over a region R, the region is divided into rectangles when we work with polar coordinates (r,8), it is natural to divide R into "polar rectangles". 13 Multiple Integral Suppose that a function f (r, 0) is defined over a region R bounded by the rays e = a and e = B and the continuous curves r= fi(0) and r = f(0) as shown in the figure below: G-T/2 r= /2(0) t
Transcribed Image Text:78 l all ? 2_52606602927270... 2 Jo L b) ly- f x* 8(x, y)dA = S, " x?dxdy 12 Multiple Integral (1,1) = H dy =(2y- y*)" - y^) dy = (8y - 12y +6ys - y - y")dy =, (8y* - 12y* + 6y - 2y) dy =(4y - 6y* + 3y5- y)dy -厚 3x11 V 105 Ry = %3D H.W. Find l, ly,Ry and Ry Integration in Polar Coordinates: To find the integral of a function f(x, y) over a region R, the region is divided into rectangles when we work with polar coordinates (r,8), it is natural to divide R into "polar rectangles". 13 Multiple Integral Suppose that a function f (r, 0) is defined over a region R bounded by the rays e = a and e = B and the continuous curves r= fi(0) and r = f(0) as shown in the figure below: G-T/2 r= /2(0) t
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