Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a sample of size 261 with 188 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. Confidence interval = Express the same answer as a tri-linear inequ
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Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a sample of size 261 with 188 successes.
- Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.
Confidence interval =
- Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <
- Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places. p = ±
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- A History professor at a local community college wants to estimate the percent of college students that cheat on online assessment. Out of 600 college students sampled, 390 had cheated. Based on this, construct a 90% confidence interval for the proportion p of college students that have cheated in his history class. Make sure to express your answers as decimals, to three places. < p < 0.682 Use the point estimate and margin of error to express the same answer. Give your answers as decimals, correctly to three places. p =We wish to estimate what percent of adult residents in a certain county are parents. Out of 300 adult residents sampled, 75 had kids. Based on this, construct a 95% confidence interval for the proportion p of adult residents who are parents in this county.Express your answer in tri-inequality form. Give your answers as decimals, to three places. < p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = ±± Submit QuestionQuestion 22We wish to estimate what percent of adult residents in a certain county are parents. Out of 500 adult residents sampled, 220 had kids. Based on this, construct a 95% confidence interval for the proportion p of adult residents who are parents in this county.Express your answer in tri-inequality form. Give your answers as decimals, to three places. < p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = ±±
- We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 172 had kids. Based on this, construct a 95% confidence interval for the proportion p of adult residents who are parents in this county.Express your answer in tri-inequality form. Give your answers as decimals, to three places. < p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = ±We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 192 had kids. Based on this, construct a 99% confidence interval for the proportion p of adult residents who are parents in this county.Express your answer in tri-inequality form. Give your answers as decimals, to three places.< p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = ±±In a survery of 199 households, a Food Marketing Institute found that 65 households spend more than $125 a week on groceries. Please find the 90% confidence interval for the true proportion of the households that spend more than $125 a week on groceries. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.Confidence interval = Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = ±±
- The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 65.7 for a sample of size 24 and standard deviation 21.8. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 90% confidence level). Assume the data is from a normally distributed population. Enter your answer as a tri-linear inequality accurate to three decimal places.The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 52.4 for a sample of size 25 and standard deviation 8.5. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 98% confidence level). Assume the data is from a normally distributed population. Enter your answer as a tri-linear inequality accurate to three decimal places. < μμ <The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 24.2 for a sample of size 26 and standard deviation 21.8. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 90% confidence level). Assume the data is from a normally distributed population. Enter your answer as a tri-linear inequality accurate to three decimal places. < μ <The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 25.4 for a sample of size 29 and standard deviation 14.8. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 90 % confidence level). Assume the data is from a normally distributed population. Enter your answer as a tri-linear inequality accurate to three decimal places.In a random sample of nine people the main driving distance to work was 21.2 miles and the standard deviation was 4.2 miles assume that the population is normally distributed construct a 95% confidence interval for the mean write your answer as an inequality including units.We wish to estimate what proportion of adult residents in a certain county are parents. Out of 300 adult residents sampled, 195 had kids. Based on this, construct a 85% confidence interval for the proportion p of adult residents who are parents in this county.Express your answer in tri-inequality form. Give your answers as decimals, to three places. < p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = ±±Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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