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An ideal Otto cycle engine with 15% clearance operates on 0.227 kg/s of air; intake state is 100 kPa, 37.7°C. The energy released during combustion is 110 kJ/s. For hot-air standard with k = 1.32, compute (a) p, V, and T at each corner, (b) W, (c) e, and (d) pm. Ans: (a) 0.2013 m³/s, 0.02626 m³/s, 596.2 K, 1479.85 kPa, 1136.4 K, 2820.7 kPa, 592.2 K, 191.71 kPa; (b) 52.7 kJ/s; (c) 47.91%; (d) 301.1 kPa

An ideal Otto cycle engine with 15% clearance operates on 0.227 kg/s of air; intake state is 100 kPa, 37.7°C. The energy released during combustion is 110 kJ/s. For hot-air standard with k = 1.32, compute (a) p, V, and T at each corner, (b) W, (c) e, and (d) pm. Ans: (a) 0.2013 m³/s, 0.02626 m³/s, 596.2 K, 1479.85 kPa, 1136.4 K, 2820.7 kPa, 592.2 K, 191.71 kPa; (b) 52.7 kJ/s; (c) 47.91%; (d) 301.1 kPa

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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4.) An ideal Otto cycle engine with 15% clearance operates on 0.227 kg/s of air; intake state is 100 kPa, 37.7°C. The energy released during combustion is 110 kJ/s. For hot-air standard with k = 1.32, compute (a) p, V, and T at each corner, (b) W, (c) e, and (d) pm. Ans: (a) 0.2013 m³/s, 0.02626 m³/s, 596.2 K, 1479.85 kPa, 1136.4 K, 2820.7 kPa, 592.2 K, 191.71 kPa; (b) 52.7 kJ/s; (c) 47.91%; (d) 301.1 kPa
Transcribed Image Text:4.) An ideal Otto cycle engine with 15% clearance operates on 0.227 kg/s of air; intake state is 100 kPa, 37.7°C. The energy released during combustion is 110 kJ/s. For hot-air standard with k = 1.32, compute (a) p, V, and T at each corner, (b) W, (c) e, and (d) pm. Ans: (a) 0.2013 m³/s, 0.02626 m³/s, 596.2 K, 1479.85 kPa, 1136.4 K, 2820.7 kPa, 592.2 K, 191.71 kPa; (b) 52.7 kJ/s; (c) 47.91%; (d) 301.1 kPa
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