An electric switch manufacturing company is trying to decide between three different assembly methods. Method A has an estimated first cost of $35,000, an annual operating cost (AOC) of $9,000, and a service life of 2 years. Method B will cost $75,000 to buy and will have an AOC of $5,500 over its 4-year service life. Method C costs $125,000 initially with an AOC of $5,500 over its 8-year life. Methods A and B will have no salvage value, but Method C will have equipment worth 11% of its first cost. Perform a future worth analysis to select the method at /= 13% per year. The future worth of method A is $ -207859.7 x The future worth of method B is $ -148961.4 The future worth of method C is $ -388715.15 Method A is selected.

FINANCIAL ACCOUNTING
10th Edition
ISBN:9781259964947
Author:Libby
Publisher:Libby
Chapter1: Financial Statements And Business Decisions
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MN.44.

 

An electric switch manufacturing company is trying to decide between three different assembly methods. Method A has
an estimated first cost of $35,000, an annual operating cost (AOC) of $9,000, and a service life of 2 years. Method B will
cost $75,000 to buy and will have an AOC of $5,500 over its 4-year service life. Method C costs $125,000 initially with an
AOC of $5,500 over its 8-year life. Methods A and B will have no salvage value, but Method C will have equipment worth
11% of its first cost.
Perform a future worth analysis to select the method at /= 13% per year.
The future worth of method A is $
-207859.7 *
The future worth of method B is $ -148961.4 *
The future worth of method C is $ -388715.15
Method A
is selected.
Transcribed Image Text:An electric switch manufacturing company is trying to decide between three different assembly methods. Method A has an estimated first cost of $35,000, an annual operating cost (AOC) of $9,000, and a service life of 2 years. Method B will cost $75,000 to buy and will have an AOC of $5,500 over its 4-year service life. Method C costs $125,000 initially with an AOC of $5,500 over its 8-year life. Methods A and B will have no salvage value, but Method C will have equipment worth 11% of its first cost. Perform a future worth analysis to select the method at /= 13% per year. The future worth of method A is $ -207859.7 * The future worth of method B is $ -148961.4 * The future worth of method C is $ -388715.15 Method A is selected.
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