An analyst of EDSA Sang Hotel sampled 20 customers from last year's records and found out that the mean sale per customer was $500 with a standard deviation of $110. A random sample of 25 customers from this year's record yielded an average sale per customer of $540 with a standard deviation of S125. Assuming the sales per customer are normally distributed, can we conclude that there has been a significant change in the average sales per customer? n₁ 1₂₂ df t= X₁ X₂ alpha (₁-x₂)-(₁-₂) + s₁² (m₁ − 1) + s₂² (m₂ − 1) 1 m+1₂-2 m 1 122₂ = S₁ S₂2₂ t2alpha/2.df

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An analyst of EDSA Sang Hotel sampled 20 customers from last year's records and found out that the
mean sale per customer was $500 with a standard deviation of $110. A random sample of 25 customers
from this year's record yielded an average sale per customer of $540 with a standard deviation of S125.
Assuming the sales per customer are normally distributed, can we conclude that there has been a
significant change in the average sales per customer?
n₁
1₂
df
t =
t =
X1
X₂
alpha
(₁-x₂)-(μ₁ −μ₂)
s₁² (m − 1) + s₂² (m₂ − 1) 1 1
1+1₂2=2
Vm
1₂
S₁
S₂
t2alpha/2.df
Transcribed Image Text:An analyst of EDSA Sang Hotel sampled 20 customers from last year's records and found out that the mean sale per customer was $500 with a standard deviation of $110. A random sample of 25 customers from this year's record yielded an average sale per customer of $540 with a standard deviation of S125. Assuming the sales per customer are normally distributed, can we conclude that there has been a significant change in the average sales per customer? n₁ 1₂ df t = t = X1 X₂ alpha (₁-x₂)-(μ₁ −μ₂) s₁² (m − 1) + s₂² (m₂ − 1) 1 1 1+1₂2=2 Vm 1₂ S₁ S₂ t2alpha/2.df
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