Accordiny queru Nomal (maxinumi) bendiiy moment f spress. © Maximun shear fore. and apresk. whue extreme fibre y= 0.3019 m M= maximum C-a:32 KNom) Iyx = 739X 106 mm4 739X10x102m メ× OY Henu: 2:32x103 x 0:3019 739X16-6 0.9477 MPca ニ maximum sheas spess (7) = VQ コ6 Also: The V- maximum aheas fore Ixx= 739x 106 mm4 or 739x10-my O L0303 m. b= 0.3304 A = 1790.3 Xió6 m² 0.49 X10x 1798.3×106x0·10303 739x 106 O: 3304 371.8 N/m? 2 N.
Accordiny queru Nomal (maxinumi) bendiiy moment f spress. © Maximun shear fore. and apresk. whue extreme fibre y= 0.3019 m M= maximum C-a:32 KNom) Iyx = 739X 106 mm4 739X10x102m メ× OY Henu: 2:32x103 x 0:3019 739X16-6 0.9477 MPca ニ maximum sheas spess (7) = VQ コ6 Also: The V- maximum aheas fore Ixx= 739x 106 mm4 or 739x10-my O L0303 m. b= 0.3304 A = 1790.3 Xió6 m² 0.49 X10x 1798.3×106x0·10303 739x 106 O: 3304 371.8 N/m? 2 N.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Find the factor of safety
Transcribed Image Text:100 N/m
500 N.m
В
A
250N
- 1-
200N/m
4
3
3
- 2
L203X203X12.7
C310X45
305X305X15
Transcribed Image Text:Acuording
to the question
have to find ;
Nomal (maxinuumi)
bendiiy moment f spes .
O Maximum sheer fore. aud spress.
M
す
whe
expeme fitre
y= 0.3019 m
yo
M= maximum (-2:32 KN.m)
Iyx =
739X 106 mm4
739X10x102
メ×
OY
Henu :
3
2.32X10
x 0:3019
739X10-6
0.9477 MPa
sheas spess )= VQ
I6
Also:
The
maximunm
V- maximunm shear force
Ixx= 739x 106 mmy
or 739x10=my
O L0303
b- 0:3304
; A = 1790.3
て-
0.49X10°× 1798.3x106x0.10303
%3D
737x 106
x 0.3304
371.8 N/m²
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