A3) A particle is projected at an angle of 8° below the horizontal from a point at the top of a vertical cliff 26 m high. The particle strikes horizontal ground at a distance 8 m from the foot of the cliff 2 s after the instant of projection. Find: (i) (ii) the speed of projection of the particle and the value of 0°, the direction of motion of the particle immediately before it strikes the ground. (i) x = v, cos et 8 * vo cos e - (1) 2 1 y = vo sin 0 t 1 : -26 = v, sin 8 (2) –(9.81)(2)² * vo sin e = -3.19 - -(2) (1)² + (2)²: v3 = (4² + 3.19²) = 26.176 = vo = 5.1 m/s from (2): 0 = 38.6° (ii) Vy = v, sin e – gt Just before striking gound: v, = -3.19 – (9.81)(2) = –22.81 m/s %3D |vy| 22.81 - tan a = 4 : a = 80.05° below the horizontal

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A3) A partiele is projected at an angle of 8° below the horizontal from a point at the top of a vertical cliff
26 m high. The particle strikes horizontal ground at a distance 8 m from the foot of the cliff 2 s after the
instant of projection. Find:
(i)
the speed of projection of the particle and the value of 0°,
(ii)
the direction of motion of the particle immediately before it strikes the ground.
(i)
X = vo cos e t
8
* Vo cos e
(1)
2
1
y = v, sin e t-
gt2
: -26 = vo sin 8 (2) –(9.81)(2)?
* vo sin e = -3.19
-(2)
- - -
(1)2 + (2)²: v3 = (4² + 3.192) = 26.176 = v = 5.1 m/s
from (2): 0 = 38.6°
(ii)
Vy = v, sin e – gt
Just before striking gound: v, = -3.19 – (9.81)(2) = -22.81 m/s
11
|v,| 22.81
.. tan a
4
.. a = 80.05° below the horizontal
Transcribed Image Text:A3) A partiele is projected at an angle of 8° below the horizontal from a point at the top of a vertical cliff 26 m high. The particle strikes horizontal ground at a distance 8 m from the foot of the cliff 2 s after the instant of projection. Find: (i) the speed of projection of the particle and the value of 0°, (ii) the direction of motion of the particle immediately before it strikes the ground. (i) X = vo cos e t 8 * Vo cos e (1) 2 1 y = v, sin e t- gt2 : -26 = vo sin 8 (2) –(9.81)(2)? * vo sin e = -3.19 -(2) - - - (1)2 + (2)²: v3 = (4² + 3.192) = 26.176 = v = 5.1 m/s from (2): 0 = 38.6° (ii) Vy = v, sin e – gt Just before striking gound: v, = -3.19 – (9.81)(2) = -22.81 m/s 11 |v,| 22.81 .. tan a 4 .. a = 80.05° below the horizontal
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