2. Given the following data of a closedtraverseLINEDISTANCE (m)BEARING1-2152N 21°00' E2-398S 87°00' E3-4S 44°00' W4-5S 10°00' W5-175N 70°00' Wa. Determine the distance of line 3-4b. Determine the distance of line 4-5

Azimuth of 1-2=21°00Azimuth of 2-3=180-87°00=93°Azimuth of 3-4=180+44°00=224°Azimuth of…

Answered: a. Determine the distance of line 3-4…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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13. Given the following data from a balanced traverse, find the area of the traverse by DMD method. LINE ADJ. DEP. ADJ. LAT 1-2 +3.14 -18.55 2-3 -55.05 +9.45 3-4 -3.53 +19.51 4-1 +55.44 -10.41
5.10 through 5.15 Locate the centroid of the plane area shown.
Given the corrected latitudes and departures of a closed traverse, Compute the DMD of line 3 - 4. Compute the DPD of line 4 - 5. Compute the area of a closed traverse in hectares. a. b. C. LINES LATITUDE DEPARTURE 1-2 +80.16 -40.12 -36.82 +50.42 2-3 -40.13 3-4 +70.18 -30.14 4-5 +30.36 5-6 +60.20 -52.34 6-1 -140.27 +48.50
In the segment 2, is it not considered a semicircular arc? since the point of the radius comes from the origin?
1. Given the following data of a closed traverse: a. use sine law to determine the distance of line 3-4 b. use sine law to determine the distance of line 4-5
Q2/B- A rough sketch of the situation is shown in Fig. PABCQP is a closed traverse. Lengths of lines CQ and QP are to be determined. Compute the latitudes and departures as shown in the table. Assume that the length of CQ = L1 and that of QP =L2. Line 12888 PA AB BC CQ QP Length 150 500 300 L₁ L₂ Bearing N10° 15'E N32° 45'E N65° 30'E $50° 30'E S68° 45'W Latitude 147.6 420.52 124.41 0.6361L₁ 0.3624L₂ Departure 26.69 270.49 272.99 0.77164₁ 0.932L₂
Please provide a scanned written or computerized clear and complete step-by-step solutions.
Please show legible illustration and solution
G
Determine the coordinates of the centroid of the shaded area. 1.7" 3.3" 6.9"- Answers: (X,Y) =( i ) in. 1.162 i 1.112
B. Profile Leveling Station BM Road 0+00 0+20 1+00 2+00 2+60 3+00 3+90 4+00 4+35 TP1 5+00 5+54 5+74 5+94 6+00 7+00 TP2 8+00 9+00 9+25.2 9+25.3 9+43.2 BM Store Σ BS 10.15 7.34 2.56 HI FS 11.47 5.26 0.76 IFS 9.36 9.80 6.50 4.30 3.70 7.10 11.70 11.20 9.50 8.40 11.08 10.66 11.06 10.50 4.40 1.20 3.90 3.40 4.60 2.20 Elevation 360.48 ft
Given the following information from a profiled line: STA 8+50 elevation = 132.74 STA 12+50 elevation = 246.29 Compute the siope of the line between these two stations

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a. Determine the distance of line 3-4 b. Determine the distance of line 4-5