A vertical road was designed with three tangent lines having a grade of 7.9%, -4.3%, and 3.3%, consecutively. The intersections of the three lines are known to be V1 and V2 having an elevation of 228.97m and 203.48m respectively. The said tangent lines will te connected by a summit and a sag unsymmetrical parabolic curve which meets at point A having an elevation of 217.74m above sea level. The L1 of the summit curve is 109.19m and the maximum offset of the sag curve is 0.65 multiplied to the maximum offset of the summit curve. Point A is located at the line that connects the two vertices. What is the value of the L2 of the sag curve in meters?

A vertical road was designed with three tangent lines having a grade of 7.9%, -4.3%, and 3.3%, consecutively. The intersections of the three lines are known to be V1 and V2 having an elevation of 228.97m and 203.48m respectively. The said tangent lines will te connected by a summit and a sag unsymmetrical parabolic curve which meets at point A having an elevation of 217.74m above sea level. The L1 of the summit curve is 109.19m and the maximum offset of the sag curve is 0.65 multiplied to the maximum offset of the summit curve. Point A is located at the line that connects the two vertices. What is the value of the L2 of the sag curve in meters?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Two grade lines, SE and EA, having a slope of +4.5% and -2.8% respectively intersect at point E. Given elevations of points S, E, and A at 94.30m, 101m, and 96.5m respectively, determine the elevation of the summit of the 120m parabolic vertical curve to connect the grade lines.
Two tangents intersect at V with back tangent having a grade of -4.5% and forward tangent of 5.5%. A 200 m curve lies on the side of PC and 102.5 on the other side. Stationing of V is at 10+538 having an elevation of 104 m. If a bridge is located above the curve, with its centerline having an elevation of 118.5 m and stationing of 10+555, with underside of the bridge located 55 cm below the given elevation, determine the height of highest vehicle it can accommodate if the bridge has a width of 12 m.
A vertical road was designed with three tangent lines having a grade of 7.3%, -3.9 %, and 2.8%, consecutively. The intersections of the three lines are known to be V1 and V2 having an elevation of 226.10m and 202.03m respectively. The said tangent lines will be connected by a summit and a sag unsymmetrical parabolic curve which meets at point A having an elevation of 216.29m above sea level. The L1 of the summit curve is 106.73m and the maximum offset of the sag curve is 0.51 multiplied to the maximum offset of the summit curve. Point A is located at the line that connects the two vertices. What is the elevation at the end of the road in meter?
Three roads are to be connected by a reversed curve. Road 1 has a length of 57.6 m. bearing due east, Road 2 has a length of 91.5 bearing N680E, and Road 3 has a length of 109.2 bearing S480E. Find the length of the common radius of the new centerline of the three roads (the common radius of the reversed curve) Show the illustration:
A vertical curve parabolic curve connects a 5% and -7% grade. The point of intersections is located at station 2+100 and the elevation is 35 m. The length of the curve at the left side of the vertex is 60 m and 80 m on the other side. Determine the location of the summit.
Sag Curve: A grade from the PVC to the PVI is -6% and from PVI to PVT is +2%. It is required to connect these grade lines with a vertical parabolic curve will pass 3.0 m. directly above the PVI. 11. Determine the length of this curve. a) 420 m b) 380 m c) 400 m d) 300 m 12. Determine the location of the lowest point measured from the PVT. a) 100m b) 75m c) 100m d) 225m 13. Compute the vertical offset at a point on the curve 100m from the PVC. a) 2.45m b) 2.33m c) 1.56m d) 1.33m
Two tangents intersect at V with back tangent having a grade of -4.5% and forward tangent of 5.5%. A 200 m curve lies on the side of PC and 102.5 on the other side. Stationing ofV is at 10+538 having an elevation of 104 m. If a bridge is located above the curve, with its centerline having an elevation of 118.5 m and stationing of 10+555, with underside of the bridge located 55 cm below the given elevation, determine the height of highest vehicle it can accommodate if the bridge has a width of 12 m.
The reduced level at the intersection of a rising gradient of 1.7% and a falling gradient of 2.3% on a proposed road is 52.50m. Given that K value is 55. The throught chainage of the intersection point is 4020m and proposed vertical curve is to have equal tangent. As a civil engineering you are required to prepare the following vertical curve design calculations : A) The through chainage of the points of the vertical curve if the minimum required length is to be used (LV) and the vertical curve setting out data at 20 metres interval. b) The chainage and reduced level of the highest point on the curve. c) Through chainage at highest point was located exactly under a bridge, if the RL of soffit is 57.42m, calculate the headroom based on proposed vertical curve design.