A random sample of size 36 is taken from a normal population having a mean of 75 and a standard deviation of 5. A second random sample of size 49 is takenfrom a different normal population having a mean of 60 and a standard deviation of 6. Find the probability that the sample mean computed from the 36measurements will exceed the sample mean computed from the 49 measurements by at least 13.1 but less than 15.7. Assume the difference of the means tobe measured to the nearest tenth.Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table......The probability is(Round to four decimal places as needed.)

Answered: Image /qna-images/answer/17c75701-3c2e-4481-95e7-392379213d38.jpg

Answered: A random sample of size 36 is taken…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A population is known to be normally distributed with standard deviation known to be 6.3. In order to test the hypothesis that the true value of the mean is 19 researchers collect a sample of size 36 and calculate the sample mean to be 16. State the distribution of the sample mean and then test this hypothesis using the appropriate test.
Do the mean weights of male college freshmen and male college seniors differ? There are arguments for and against this question. The mean weight, μx of college freshmen will be compared to the mean weight, My of college seniors. The true values of Mx and My are unknown. It is recognized that the true standard deviations are x = 13 for male college freshmen and dy = 24 for male college seniors. We take a random sample of m = 431 college freshmen and a random sample of n=289 college seniors. The mean weights were x = 178 for male college freshmen and y = 185 for male college seniors. Assuming independence between the samples and assuming the weights are normally distributed we would like to estimate My - My. a) What is the standard deviation of the distribution of x?[ b) What is the standard deviation of the distribution of x-y? c) Create a 95% confidence interval for Mx - Hy? d) What is the length of the confidence interval in part c) ? e) If we let n stay at 289 but vary m, what is the…
A random sample of 25 night students was taken with a sample mean GPA of 2.86 and a standard deviation of 0.06. A random sample of 30 day students was taken with a sample mean GPA of 2.88 and a standard deviation of 0.07. Test the claim that the mean GPA of night students (μ) is different from the mean GPA of day students (μD) at a = 0.05. Assume that the data come from normal populations with unequal variances. Round your answers to three decimal places, and round any interim calculations to four decimal places. Fill in the hypotheses below (click the circle to the left of the correct answer): Ho: ên p σ΄ UN Td μD = v pО µÑ¯ Êµ¯Ñ¿© µD Ha: pOād up μι ên # PO μN X d This test is two-tailed. What is the test statistic? HD ên Part 2 of 4
Suppose that the hemoglobin levels among healthy females are normally distributed with a mean of 14.1 gdL. Research shows that exactly 95% of healthy females have a hemogoblin level of 16.1 gdL. What is the standard deviation of the distribution of hemoglobin levels and healthy females. Carry you intermediate computations to atleast four decimal places, and round your answer to at least two decimal places.
To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 43 feet. Assume the population standard deviation is 4.6 feet. The mean braking distance for Make B is 46 feet. Assume the population standard deviation is 4.5 feet. At α=0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles? Assume the samples are random and independent, and the populations are normally distributed. The critical value(s) is/are Find the standardized test statistic z for μ1−μ2.
A psychologist obtains a random sample of 30 mothers in the first trimester of their pregnancy. The mothers are asked to play Mozart in the house at least 45 minutes each day until they give birth. We know that IQs are normally distributed with a mean of 100. A few years after their births the children were given an IQ test and the IQs of the 30 children in the study resulted in a sample mean of 104.2. Assume the population standard deviation for IQ of children is 15. Is there evidence that the children who listen to Mozart for at least 45 minutes each day during pregnancy have higher IQs at the 0.05 level of significance? Step 1: Define the parameter & setup the testStep 2: State the Level of SignificanceStep 3: Find the value of the Test StatisticsStep 4: Find P-Value OR Find Critical ValueStep 5: State Conclusion and why
To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 41 feet. Assume the population standard deviation is 4.6 feet.The mean braking distance for Make B is 42 feet. Assume the population standard deviation is 4.4 feet. At α=0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles? Assume the samples are random and independent, and the populations are normally distributed. Complete parts (a) through (e). (a) Identify the claim and state Ho and Ha. What is the claim? A.The mean braking distance is different for the two makes of automobiles. This is the correct answer. B.The mean braking distance is the same for the two makes of automobiles. C.The mean braking distance is less for Make A automobiles than Make B automobiles. Your answer is…
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of O°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. If 1.7% of the thermometers are rejected because they have readings that are too high and another 1.7% are rejected because they have readings that are too low, find the two readings that are cutoff values separating the rejected thermometers from the others. interval of acceptable thermometer readings = ɔ.
a distribution with a mean of u=41 and a standard deviation of 4 is transformed into a standardized distribution with a mean of u=100 and a standardized deviation =20, find the new standardized score for each of the following values from the original population, x=39, x=36, x=45, x=50
A nutritionist claims that the mean tuna consumption by a person is 3.6 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.4 pounds per year. Assume the population standard deviation is 1.11 pounds. At α=0.06, can you reject the claim?
In order to have the standard error of the mean be 6, one would need to take a sample of size from a normally distributed population with a standard deviation of 42
A statistician wishing to test a hypothesis that students score at most 75% on the final exam in an introductory statistics course decides to randomly select 20 students in the class and have them take the exam early. The average score of the 20 students on the exam is 72% and the standard deviation in the population is known to be = 15%. The statistician calculates the test statistic to be –0.8944. If the statistician chose to do a two-sided alternative, the P-value would be calculated by: a. finding the area to the right of –0.8944 and doubling it. b. finding the area to the left of –0.8944 and doubling it. c. finding the area to the right of the absolute value of –0.8944 and dividing it by two. d. finding the area to the left of –0.8944

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