A proton with a kinetic energy of 4.7x10-16 J moves perpendicular to a magnetic field of 0.24 T What is the radius of its circular path? Express your answer using two significant figures.

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A proton with a kinetic energy of 4.7×10-16
J
moves perpendicular to a magnetic field of 0.24
T
What is the radius of its circular path?
Express your answer using two significant figures.
Transcribed Image Text:A proton with a kinetic energy of 4.7×10-16 J moves perpendicular to a magnetic field of 0.24 T What is the radius of its circular path? Express your answer using two significant figures.
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