A proposed method for generating electricity from solar irradiation is to concentrate the irradiation into a cavity that is placed within alarge container of a salt with a high melting temperature. If all heat losses are neglected, part of the solar irradiation entering the cavityis used to melt the salt while the remainder is used to power a Rankine cycle. (The salt is melted during the day and is resolidified atnight in order to generate electricity around the clock.)9R =Est-3.45 MWiSaltTsalt = 1000°CMirrorMWqRConsider conditions for which the solar power entering the cavity is asol = 7.10 MW and the time rate of change of energy stored inthe salt is Est = 3.45 MW. For a cavity opening of diameter D, = 1 m, determine the rate of heat transfer to the Rankine cycle, qr, inMW. The temperature of the salt is maintained at its melting point, Tsalt = Tm= 1000°C. Neglect heat loss by convection andirradiation from the surroundings.SunHeliostats

Write the given data. qsol=7.10 MWE˙st=3.45 MWDs=1 mTsalt=Tm=1000 °C

A proposed method for generating electricity from solar irradiation is to concentrate the irradiation into a cavity that is placed within a large container of a salt with a high melting temperature. If all heat losses are neglected, part of the solar irradiation entering the cavity is used to melt the salt while the remainder is used to power a Rankine cycle. (The salt is melted during the day and is resolidified at night in order to generate electricity around the clock.) Est-3.45 MW 9R = Salt Tsalt = 1000°C Mirror MW 9R Sun Consider conditions for which the solar power entering the cavity is asol = 7.10 MW and the time rate of change of energy stored in the salt is Est = 3.45 MW. For a cavity opening of diameter D, = 1 m, determine the rate of heat transfer to the Rankine cycle, qr, in MW. The temperature of the salt is maintained at its melting point, Tsalt = Tm= 1000°C. Neglect heat loss by convection and irradiation from the surroundings. Heliostats

A proposed method for generating electricity from solar irradiation is to concentrate the irradiation into a cavity that is placed within a large container of a salt with a high melting temperature. If all heat losses are neglected, part of the solar irradiation entering the cavity is used to melt the salt while the remainder is used to power a Rankine cycle. (The salt is melted during the day and is resolidified at night in order to generate electricity around the clock.) Est-3.45 MW 9R = Salt Tsalt = 1000°C Mirror MW 9R Sun Consider conditions for which the solar power entering the cavity is asol = 7.10 MW and the time rate of change of energy stored in the salt is Est = 3.45 MW. For a cavity opening of diameter D, = 1 m, determine the rate of heat transfer to the Rankine cycle, qr, in MW. The temperature of the salt is maintained at its melting point, Tsalt = Tm= 1000°C. Neglect heat loss by convection and irradiation from the surroundings. Heliostats

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Please explain with steps.
A drying oven consists of a long semicircular duct of diameter D=1 m. Materials to be dried cover the base of the oven while the wall is maintained at 1200 K. Length of the oven (into paper direction) is 1 m. Water coated material is maintained at 325 K. Assume both the wall and the material to be blackbodies. (1) What is heat transfer rate? (2) Given at temperature 325 K, water needs heat 2.378 × 106 J/kg in order to be dried (from liquid water to steam). How much water can be dried per second based on the heat transfer rate from (1)? T₁ = 1200 K T₂ = 325 K — D = 1 m D= m→
13.58 The end of a cylindrical liquid cryogenic propellant tank in free space is to be protected from external (solar) radi- ation by placing a thin metallic shield in front of the tank. Assume the view factor F, between the tank and the shield is unity; all surfaces are diffuse and gray, and the surroundings are at 0 K. T Shield, T, T, = 100 K E1 = E2 = 0.05 &= 0.10 Ĝ3 = 1250 W/m? Tank Solar irradiation Gs Find the temperature of the shield T, and the heat flux (W/m) to the end of the tank.
2 parts ( C&D) Read and solve carefully please write clearly and box the final answer(s) label them Hint: Pay attention to numbers bolded
13.41 Consider two very large parallel plates with diffuse, gray surfaces. - T, = 1000 K, ɛ, = 1 T, = 500 K, ez = 0.8 Determine the irradiation and radiosity for the upper plate. What is the radiosity for the lower plate? What is the net radiation exchange between the plates per unit area of the plates?
Two parallel gray planes have emissivities of 0.8 and 0.7 and are maintained at 800°C and 1500°C. What is the net radiation energy exchange? What would be the reduction in heat transfer if radiation shield of polished aluminums =0.04 is placed between them.
For a surface, how is irradiation defined? For diffusely incident radiation, how is irradi ation on a surface related to the intensity of incident radiation?
An opaque surface has the spectral, hemispherical reflectivity distribution as shown below. The surface receives the spectral irradiation shown below. A. Determine the total irradiation on the surfaceB. Determine the radiant flux that is absorbed by the surface
6.4 Two large diffuse parallel plates are maintained at temperatures T₁ = 1400 K and T₂ = 700 K. The plates are made from the same metal, and their spectral emissivities as a function of wavelength, &, are approximated as shown by two constant values joined by a linear decrease with wavelength. Compute the net radiant energy flux being transferred from plate 1 to plate 2. What is the energy flux if both plates are assumed gray with an approximate average emissiv- ity of 0.5 applied over the entire spectral range? 91 T₁ = 1400 K, Ex T₂ = 700 K, EX 92-91 0.85 Ex 0.15 0 Answer: q₁106,850 W/m²; 91.gray = 68,070 W/m². 2 λ (μm) 7
Question 30 of 30 く - / 4.3 View Policies Current Attempt in Progress Two concentric spheres of diameter D = 0.8 m and D2 = 1.2 m are separated by an air space and have surface temperatures of T = 410 K and T2 = 300 K. (a) If the surfaces are black, what is the net rate of radiation exchange between the spheres, in W? 912 = W (b) What is the net rate of radiation exchange between the surfaces if they are diffuse and gray with &j = 0.5 and ɛ2 = 0.05, in W? 912 = i W (c) What is the net rate of radiation exchange if D2 is increased to 20 m, with ɛ2 = 0.05, ɛ = 0.5, and D = 0.8 m, in W? 912 = W (d) What is the net rate of radiation exchange if the larger sphere behaves as a black body (ɛ2 = 1.0) and with &j = 0.5, D2 = 20 m, and D = 0.8 m, in W? 912 = i W Physical Properties Mathematical Functions II
A 5 mm-thick steel firewall is suddenly exposed to a radiant heat source that can be approximated as a blackbody at 1000K. How long will it take for the surface to reach 500 K if the initial temperature of the wall is 300K?