A R-134a home refrigerator operates on a simple cycle at pressures 1.8 bar-abs and 7.5 bar-abs. Therefrigerant mass flow-rate is 0.005 kg/s. Fill up Tables 3a and 36.Part 3. Calculation: Performance of a Simple Refrigeration Cycle.Table Ja. Selected Thermodynamic properties of R-134a refrigerant according to the given cycle.kJ/ kga Specific Enthalpy at suctionA Specific volume at suctionm/ kgkJ /g-Ke Specific entropy at suctiond Specific enthalpy at dischargeSpecific enthalpy after expansion hs431kJ/ kgkJ / kgTable 3b. Performance of the home refrigerator according to its cycle of operation.kWatta. Evaporator cooling capacityb Condenser heat rejection rateQ CondkWattPower required by compressorW CompC.kWattd Volume displacement of compressore. Coefficient of Performance-RefVCampLi/sCOP Reff Coefficient of Performance-CanotCOP RC& Flash-gas formed after expansionX4kg / kg%3D

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A K-134a home refrigerator operates on a simple cycle at pressures L.8 bar-abs and 7.5 bar-abs. refrigerant mass flow-rate is 0.005 kg/s. Fill up Tables 3a and 36. Part 3. Calculation: Performance of a Simple Refrige Table Ja. Selected Thermodynamic properties of R-134a refrigerant according to the given eycle. kJ/ kg a Specific Enthalpy at suction A Specific volume at suction m n³/kg kJ /g-K 31 e Specific entropy at suction kJ/ kg h2 d Specific enthalpy at discharge kJ/kg e. Specific enthalpy after expansion h4 Table 3b. Performance of the home refrigerator according to its cycle of operation. kWatt a. Evaporator cooling capacity b Condenser heat rejection rate kWatt C. Power required by compressor W Comp kWatt d Volume displacement of compressor VCamp e Coefficient of Performance-Ref f Coefficient of Performance-Camot Li/s COP Ref COP RC & Flash-gas formed after expansion x4 kg / kg

A K-134a home refrigerator operates on a simple cycle at pressures L.8 bar-abs and 7.5 bar-abs. refrigerant mass flow-rate is 0.005 kg/s. Fill up Tables 3a and 36. Part 3. Calculation: Performance of a Simple Refrige Table Ja. Selected Thermodynamic properties of R-134a refrigerant according to the given eycle. kJ/ kg a Specific Enthalpy at suction A Specific volume at suction m n³/kg kJ /g-K 31 e Specific entropy at suction kJ/ kg h2 d Specific enthalpy at discharge kJ/kg e. Specific enthalpy after expansion h4 Table 3b. Performance of the home refrigerator according to its cycle of operation. kWatt a. Evaporator cooling capacity b Condenser heat rejection rate kWatt C. Power required by compressor W Comp kWatt d Volume displacement of compressor VCamp e Coefficient of Performance-Ref f Coefficient of Performance-Camot Li/s COP Ref COP RC & Flash-gas formed after expansion x4 kg / kg

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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A R-134a home refrigerator operates on a simple cycle at pressures 1.8 bar-abs and 7.5 bar-abs. The
refrigerant mass flow-rate is 0.005 kg/s. Fill up Tables 3a and 36.
Part 3. Calculation: Performance of a Simple Refrigeration Cycle.
Table Ja. Selected Thermodynamic properties of R-134a refrigerant according to the given cycle.
kJ/ kg
a Specific Enthalpy at suction
A Specific volume at suction
m/ kg
kJ /g-K
e Specific entropy at suction
d Specific enthalpy at discharge
Specific enthalpy after expansion hs4
31
kJ/ kg
kJ / kg
Table 3b. Performance of the home refrigerator according to its cycle of operation.
kWatt
a. Evaporator cooling capacity
b Condenser heat rejection rate
Q Cond
kWatt
Power required by compressor
W Comp
C.
kWatt
d Volume displacement of compressor
e. Coefficient of Performance-Ref
VCamp
Li/s
COP Ref
f Coefficient of Performance-Canot
COP RC
& Flash-gas formed after expansion
X4
kg / kg
%3D

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