Part 1: Test of Hypothesis for One and Two MeansA group of public health nutrition students determined whether mung bean (Vigna radiata) can support growth byperforming an experimental growth assay on 30 Sprague Dawley rats. Fifteen rats were randomly allocated to theexperimental group and the remaining fifteen were allocated to the control group. The rats were fed ad libitum fortwo weeks. The experimental group received feeds composed of mung bean while the control group receivedstandard rat feeds. The mean weight of both groups was taken before and after the indicated feeding period.Test the hypothesis that mung bean better supports growth of the Sprague Dawley rats than the standard rat feed.Experimental GroupControl GroupMean weight (in grams)before feedingMean weight (in grams) afterfeedingSD of weight (in grams)before feedingSD of weight (in grams) afterfeeding43.0343.8846.3094.602.733.254.763.65

Answered: Image /qna-images/answer/b331eb68-91bc-46b1-8419-5f69083ea736.jpg

Answered: A group of public health nutrition…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The leader of two postpartum women’s support groups is interested in the depression levels of the women in her groups. She administers the Center for Epidemiologic Studies Depression Scale (CES-D) screening test to the members of her groups. The CES-D is a 20-question self-test that measures depressive feelings and behaviors during the previous week. The mean depression level from the screening test for the 10 women in the first group is μ₁ = 16; the mean depression level for the 14 women in the second group is μ₂ = 10. Without calculating the weighted mean for the combined group, you know that the weighted mean is:
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
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An analysis of variance produces SSb = 40 and MSb = 20. In this analysis, how many treatment conditions are being compared?
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atients suffering from rheumatic diseases or osteoporosis often suffer critical losses in bone mineral density (BMD). Alendronate is one medication prescribed to build or prevent further loss of BMD. Holcomb and Rothenberg (A-3) looked at 96 women taking alendronate to determine if a difference existed in the mean percent change in BMD among five different primary diagnosis classifications. Group 1 patients were diagnosed with rheumatoid arthritis (RA). Group 2 patients were a mixed collection of patients with diseases including lupus, Wegener’s granulomatosis and polyarteritis, and other vasculitic diseases (LUPUS). Group 3 patients had polymyalgia rheumatica or temporal arthritis (PMRTA). Group 4 patients had osteoarthritis (OA) and group 5 patients had osteoporosis (O) with no other rheumatic diseases identified in the medical record. Changes in BMD are shown in the following table. Discuss the Alendronate medication data in terms of variability. To determine if a difference…

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