A grade of -5% grade intersects a grade of 0%. P.C. has a STATION of 10 + 110.00 which has an elevation of 300MASL. These two center gradelines are to be connected by a 200 meter symetrical vertical parabolic curve. A. ) What is the station and elevation of the LOWEST point of the vertical curve. B) What is the station and elevation of P.T

Q: The tangents of a sag curve connects at the point of intersection having Station 18+407.60 and…

A: 1. Given : At point of intersection (PI) ⇒ Station = 18 + 407.60…

Q: Problem 1 A - 4% grade meets a +5.5% grade at a vertex whose elevation equals to 132.56 m directly…

A:

Q: 3. A grade of +5% grade intersects a grade of -3.0% P.C. has a of 10 + 110.00 which has an elevation…

A:

Q: A vertical parabolic sag curve of Laon Laan underpass has a grade of -4% followed by a grade of +2%…

A: We know that ; r = g2 - g1L L = g2 - g1r where ; g2 = 2 % = 0.02 g1 = - 4 % = - 0.04 r = 0.6 % =…

Q: A - 6% grade and a + 2% grade intersect at sta. 12 + 200 whose elevation is at 45.673 m. The two…

A: PVCELV=PVIELV-g1L2PVCelv=45.673+0.06×1802PVCelv=51.073m

Q: A compound curve is laid out 480 m. from the P.C. to the P.C.C. having a radius of 763.94 m then…

A:

Q: A symmetrical parabolic curve passes through point A whose elevation is 23 23m at a distance of 54…

A: Correction in question:- As the elevation of PC is given as 22.56 m Hence, elevation of point A can…

Q: A forward tangent of +6% was designed to intersect a back tangent of  -3% at a proposed underpass…

A: GIVEN DATA:- L1 = 200m L2 = 100m g1 = -3% g2= +6% VPI 12+ 530.20 Bridge Elevation = 117.48m VPI…

Q: A grade of 5.6% meets a grade of -3.4% at Sta 16+890 whose elevation is at 370 m. A parabolic curve…

A:

Q: A downgrade of 4.6° meets an upgrade of 3.20% at Sta . 73+108 where the elevation is 998 m. A…

A: Given; downgrade = 4.6°  Sta = 73+108 elevation = 998 m. parabolic curve AB=440 m long

Q: SURVEYING 103 C2 Problem set: as An unsymmetrical parabolic curve has a forward tangent of-8% and…

A:

Q: The forward tangent of 6% was designed to intersect a back tangent of -3% at a proposed underpass…

A: Foreword tangent - 6%Back tangent- -3%elevation= 100mstationing- 12+530.200centerline of the bridge-…

Q: 7.5% grade is followed by a 1.225% grade intersecting at Sta. 15+750, with an elevation of 395.5 m.…

A:

Q: curve has a length of 141m with tangent grades of -1.5% and 2.5% intersecting at station 12+640.22…

A: PVCSTATION=PVISTA-L2PVCsta=12640.22-1412=12+569.72PVCELV=PVIELV-g1L2PVCelv=240-0.025×1412PVCelv=238.…

Q: Two tangents intersect at v with back tangent having a grade of - 2.75q and forward tangent of…

A:

Q: the tangents of a sag curve connects at the point of intersection having station 18.424.35 and…

A: This question belongs to subject surveying. In this question we find out the value of the lowest…

Q: Identify the type of vertical curve (sag or crest) by the following rates of change in grade. -0.5%…

A:

Q: A grade descending at the rate of -4% intersects another grade ascending at the rate of +8% at…

A: We have to determine the value of necessary length of the curve as per the given data in the…

Q: A – 6% grade and a 2% intersect at STA 12+200 whose elevation is at 14.375 m. The two grades are to…

A: Given data,  Sta = 12+200 Elevation of intersection = 14.375 m Grade 1 = -6% Grade = 2%

Q: A vertical parabolic curve of length 180m has the following specifications. The point of interaction…

A:

Q: A-4% grade line meets another line of +3.2% grade at station 11+ 40. If a 225-ft parabolic curve…

A: This question is related to Simple curve from Surveying Engineering. In this question we calculate…

Q: A 669m equal tangent crest vertical curve has PVC at Sta 18+662 and at elevation 199m. The initial…

A: Given- PVCSTA=18+662E=199mn1=7.25%n2=-7.42%L=669m

Q: A 1200 feet parabolic vertical curve has an entering grade of –2.6% and a departing grade of +3.4%.…

A: PVC Station…

Q: A vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation…

A: Answer  (a) Calculation of Length of vertical curve needed to make the highest point at station 150…

Q: as PVC at Sta 19+274 and at elevation 136m. The initial grade is 6.14% and the final grade is…

A: Given data PVC at Sta 19+274 elevation 136m  initial grade is 6.14% final grade is -5.58%

Q: CONNECT A FORWARD TANGENT OF 3% AND A BACK TANGENT OF-15% BY A 300 M SYMMETRICAL PARABOLIC CURVE. IT…

A: Given: The grade g1 is -15%. The grade g2 is 3%. The length of the curve is 300 m. The station at PI…

Q: (a) Station and elevation of PC & PT (b) Station of the lowest point of the curve (c) Elevation of…

A:

Q: A -2.6% grade meets a +4.8% grade near an underpass. To maintain the minimum clearance allowed under…

A:

Q: owed by a 1.25% grade intersecting at Sta. 15+750, with an elevation of 374.5 m. The change of grade…

A:

Q: Two tangents intersect at V with back tangent having a grade of -4% and forward tangent of 5%. A 205…

A:

Q: A +3.2% grade Line meets another Line of -4% grade at station 11 + 40. If a 225-ft parabolie curve…

A:

Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Drainage of Pavements

Pavement Drainage holds ample significance, as it prevents the accumulation of water or any liquid on the surface of pavements and ensures proper drainage system. With proper design and gradual slopes provided, the water gets easily removed from the surface into the drains, which are essential during heavy rains and unusual weather conditions keeping it less prone to accidents and increasing the durability of the pavement structure.