A device with mass m = 0.21 kg. Contains gas Initially with specific volume v1= 0.84 m³/kg , P1=104 kPa , T1=295 K. Gas compressed to a V2= 0.25 m³/kg , P2=633 kPa , T2=433 K. The useful work input is W=180 kJ. Po=101kPa, To=289 K and v= 0.84 m2/kg, determine

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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A device with mass m = 0.21 kg. Contains gas
Initially with specific volume v1= 0.84 m/kg
,P1=104 kPa , T1=295 K. Gas compressed to a
V2= 0.25 m³/kg, P2=633 kPa , T2=433 K. The
useful work input is W=180 kJ. Po=101kPa,
To=289 K and vo= 0.84 m³/kg , determine
Properties : R= 0.2871 kPa.m³/kg.K ( cp =
1.01 kJ/kg-K and Cy = 0.725KJ/kg-K
The exergy state (1), X1
The exergy state (2), X2
The reversible work
The second-law efficiency of the compressor
Transcribed Image Text:A device with mass m = 0.21 kg. Contains gas Initially with specific volume v1= 0.84 m/kg ,P1=104 kPa , T1=295 K. Gas compressed to a V2= 0.25 m³/kg, P2=633 kPa , T2=433 K. The useful work input is W=180 kJ. Po=101kPa, To=289 K and vo= 0.84 m³/kg , determine Properties : R= 0.2871 kPa.m³/kg.K ( cp = 1.01 kJ/kg-K and Cy = 0.725KJ/kg-K The exergy state (1), X1 The exergy state (2), X2 The reversible work The second-law efficiency of the compressor
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