A continuous beam is to be subjected to a total uniform dead load of 10 kN/m and live load of 25 kN/m. Use NSCP coefficient method. Refer to Figure - 4. U = 1.2D + 1.6L. 1. Calculate the factored moment at E. 2. Calculate the factored moment at D. 3. Determine the factored shear at D.

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Q: The beam supports the loads as shown in the figure. Using E=200 GPa, w = 16 kN/m, P = 24 kN, M = 16…

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Q: Consider the beam shown below. Take P = 5 kip and w = 1.7 kip/ft. Point E is just to the right of…

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Q: 4. Solve for the support reactions of the beam shown below using SDM. Assume beam is prismatic and…

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Q: 4. Solve for the support reactions of the beam shown below using SDM. Assume beam is prismatic and…

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Q: y 9 kips/ft 5 kips/ft A В C D 6 ft 10 ft 11 ft

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Q: Solve all reactions and the forces in every member.

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Q: PROBLEM #4: Given the beam loaded as shown in the figure. Neglecting the weight of the beam. a.…

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A: Note - value of reaction is taken as 256.738kN to avoid calculation mistakes.

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Q: The reaction at the roller support in kN.

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Q: Using E=200 GPa, w = 16 kN/m, P = 24 kN and M = 16 kNm, L7= 2 m, L2 = 6, L3= 2 m and a=20 mm. Find,…

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Q: URGENT

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System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.