A 31.9 mL sample of a 0.110 M solution of NaCN is titrated by 0.380 M HCl. Ks for CN is 2.0 x 10-5. Calculate the pH of the solution: a. prior to the start of the titration pH = b. after the addition of 6.46 mL of 0.380 M HCI pH = c. at the equivalence point pH = d. after the addition of 11.5 mL of 0.380 M HCl pH =

A 31.9 mL sample of a 0.110 M solution of NaCN is titrated by 0.380 M HCl. Ks for CN is 2.0 x 10-5. Calculate the pH of the solution: a. prior to the start of the titration pH = b. after the addition of 6.46 mL of 0.380 M HCI pH = c. at the equivalence point pH = d. after the addition of 11.5 mL of 0.380 M HCl pH =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Eq 12
name the following
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H -Cl
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hamess CH3 CH3 cH3-o cH3 cH3-CH cty
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