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- During early research in nuclear energy, why were scientists surprised that the products from splitting a uranium nucleus had less mass than the reactants? They expected that the large release of energy would cause an increase in mass. Up to that time, only chemical changes were known to form less mass than they started with. All known changes always started and ended with the same amount of mass. Other known nuclear changes resulted in the same mass of products as reactants. Next Submit Save and Exit Mark this and return centViewers/AssessmentViewer/Activit.Atomic Mass Units and e/u The atomic mass of an isotope is its mass in atomic mass units, where 1 u = 1.661 x 10-27 kg. The ratio of the fundamental charge, e, to the atomic mass unit, u, is e/u = 9.65 x 107 C/kg. 1. Using Atomic Mass Units (a) What is the mass of an isotope with an atomic mass of 19.2 u? m = 31.89e-27 kg (b) What is the charge-to-mass ratio of a +2Li-6 ion, which has an atomic mass of 6.015? 오 = 2.4e6 X C/kg mPlease help explain what steps I should take to solve this problem. Thank you. (See attached Image)
- Which of the following is measured in millimeters? a) energy resolution b) sensitivity c) field uniformity d) temporal resolutionIs it wrong to say count to the right of the decimal point to get 10^-5 for the below? Please explain, as I am a bit confused with the 10^-5, as I think to the left because of the negative. 0.000036 s = 3.60 * 10^-5 sCould I get a recheck on the answer for a and b? Here they seem to be incorrect—or at least incorrect notation. I tried 0.00049 for a, and it was also incorrect