8. Which is correct: a) Zn-in is blue b) Free EDTA is red c) ZnY is colorless d) The Free EBT indicator is red

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Chapter1: Chemical Foundations
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please solve question 8. analytical chemistry 

6. Phosphoric acid (25 mL) was titrated with sodium hydroxide (50 mL, 0.05 M) to reach Ph.Ph end point.
Calculate Mio,:
a) 0.10
b) 0.050
c) 0.025
d) 0.175
e) 0.0125
7. H20 (200 mL) was titrated with EDTA (21 mL, 0.02 M). Calculate the hardness of water (Ca=40, CO3=60 g/mol):
a) 100
b) 400
c) 301
d) 84
e) 210
8. Which is correct:
a) Zn-in is blue
b) Free EDTA is red
c) ZnY is colorless
d) The Free EBT indicator is red
9. Sn+2 solution (100 mL) was mixed with 12 (115 mL, 0.05 M). the resulting solution was titrated with
thiosulfate (22 mL, 0.05 M). Calculate the ppm of Sn+2(Sn=119 g/mol)
c) 2339 d) 4310
a) 5533 b) 1705
10. ZnSO4.7H20 (1 g, 288 g/mol) was dissolved in 100 mL solution. (10) mL was titrated with 53 mL) EDTA.
Calculate M-EDTA
c) 0.0333
d) 0.0066
a) 0.10
b) 0.175
Transcribed Image Text:6. Phosphoric acid (25 mL) was titrated with sodium hydroxide (50 mL, 0.05 M) to reach Ph.Ph end point. Calculate Mio,: a) 0.10 b) 0.050 c) 0.025 d) 0.175 e) 0.0125 7. H20 (200 mL) was titrated with EDTA (21 mL, 0.02 M). Calculate the hardness of water (Ca=40, CO3=60 g/mol): a) 100 b) 400 c) 301 d) 84 e) 210 8. Which is correct: a) Zn-in is blue b) Free EDTA is red c) ZnY is colorless d) The Free EBT indicator is red 9. Sn+2 solution (100 mL) was mixed with 12 (115 mL, 0.05 M). the resulting solution was titrated with thiosulfate (22 mL, 0.05 M). Calculate the ppm of Sn+2(Sn=119 g/mol) c) 2339 d) 4310 a) 5533 b) 1705 10. ZnSO4.7H20 (1 g, 288 g/mol) was dissolved in 100 mL solution. (10) mL was titrated with 53 mL) EDTA. Calculate M-EDTA c) 0.0333 d) 0.0066 a) 0.10 b) 0.175
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