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7) Solving quadratic equation program Let's consider the general formula of a quadratic equation : ax? + bx +c = 0 Example in the equation : x? + 3x + 8 = 0 a=1, b=3 and c=8 where a, b and c are real numbers and a # 0 To solve the equation a discriminant D is calculated as: D = b2-4ac If D is less that 0: there is no solution If D is equal to 0: there is one solution b 2a If D is greater that 0: there is two solutions x1 and x2 -b + VD x1. 2a -b-VD x2 = 2a

7) Solving quadratic equation program Let's consider the general formula of a quadratic equation : ax? + bx +c = 0 Example in the equation : x? + 3x + 8 = 0 a=1, b=3 and c=8 where a, b and c are real numbers and a # 0 To solve the equation a discriminant D is calculated as: D = b2-4ac If D is less that 0: there is no solution If D is equal to 0: there is one solution b 2a If D is greater that 0: there is two solutions x1 and x2 -b + VD x1. 2a -b-VD x2 = 2a

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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7) Solving quadratic equation program Let's consider the general formula of a quadratic equation : ax? + bx +c = 0 Example in the equation : x2 + 3x + 8 = 0 a=1, b=3 and c=8 where a, b and care real numbers and a + 0 To solve the equation a discriminant D is calculated as : D = b2 – 4ac If D is less that 0: there is no solution If D is equal to 0: there is one solution b x = 2a If D is greater that 0: there is two solutions x1 and x2 -b + VD x1 2a -b - VD x2 = 2a
Transcribed Image Text:7) Solving quadratic equation program Let's consider the general formula of a quadratic equation : ax? + bx +c = 0 Example in the equation : x2 + 3x + 8 = 0 a=1, b=3 and c=8 where a, b and care real numbers and a + 0 To solve the equation a discriminant D is calculated as : D = b2 – 4ac If D is less that 0: there is no solution If D is equal to 0: there is one solution b x = 2a If D is greater that 0: there is two solutions x1 and x2 -b + VD x1 2a -b - VD x2 = 2a
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