4. Considering the following figure with flow from A to D, compute the total head loss from A to D if the flow is 1700 liters per second. Pipe 1: Length = 1000 m; =900 mm; n = 0.011 Pipe 2: Lengt = 650 m; Ø = 450 mm; = 0.011 Pipe 3: Length = 750 m; = 600 mm; n = 0.011 Pipe 4: Length = 460 m; Ⓒ=750 mm; n = 0.011

4. Considering the following figure with flow from A to D, compute the total head loss from A to D if the flow is 1700 liters per second. Pipe 1: Length = 1000 m; =900 mm; n = 0.011 Pipe 2: Lengt = 650 m; Ø = 450 mm; = 0.011 Pipe 3: Length = 750 m; = 600 mm; n = 0.011 Pipe 4: Length = 460 m; Ⓒ=750 mm; n = 0.011

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

4) For the system given in the figure, find the elevation of Reservoir D and the flow direction in pipe 6. Neglect minor losses. El 80 m V A Pipe 1 2 3 4 ||| 5 6 L (m) 600 600 600 700 300 300 P D(mm) 600 600 450 450 450 600 El 90 m B 2 f 0.025 0.025 0.03 0.03 0.03 0.03 3 El 60 m V с 5 6 E1 = ? D
In the figure shown pipes are in parallel connection with properties given. If the flow into the system is 850lps with total head loss of 10 J/N. For the value of f=0.020 for all pipes, find the diameter of pipe 4. Pipe No. Length - m Diameter - em 1 1000 90 500 50 3 600 40 4 800 5 700 75
With velocity of 14 m/s in the 375 mm diameter pipe in the figure shown, determine the discharge in pipe 4 in m3/s. Assume f = 0.0404 for all pipes and neglect minor losses. The following are the properties of each pipe: Pipe 1 (Length=476 m, Diameter = 375 mm) Pipe 2 (Length=528 m, Diameter = 524 mm) Pipe 3 (Length=479 m, Diameter = 653 mm) Pipe 4 (Length=839 m, Diameter = 452 mm) Pipe 5 (Length=1435 m, Diameter = 435 mm) Round your answers in 4 decimal places.
What is the head that must be supplied by the pump to the water to pump 0.4 m³/s from the lower to the upper reservoir ? Hint: [The head loss in the pipes is given in the figure as a function of water velocity]. Elevation = 150m Water Elevation 100m h₁=45v²/2g d=15cm Water Pump h=22.5v²12g d=20cm Elevation 40m
Use the following given values to solve problems, unless otherwise stated. Ywater = 9790 N/m³ = 62.4 lbf/ft°; g = 9.81 m/s? = 32.2 ft/s²; 1 hp = 550 lbf-ft/s = 746 Watts Problem-1 Water is pumped from the large tank through a uniform diameter pipe (d = 3 in.) and exits as a free jet (refer figure-a). The plot of the flowrate (Q) versus pump-head (hp) is a straight-line graph that passes through points (3, 16) as shown in figure-b. If the pipe friction head loss is, hf = 7V:/2g, where V is the average fluid velocity in the pipe, find a) the equation that relates hp and Q; b) flowrate and c) If the pump is 75% efficient, what horsepower is needed to drive it? Assume steady, incompressible flow. Ignore kinetic energy correction factor (a). 12 ft Pump %3D (a) 16 3. Q, ft°ls (b) dy
Don't worry about the table
answer is given just give the solution and right answer.
The circular water pipes shown in the sketch are following full. The velocity of flow (in m/s) in the branch pipe "R" is V = 6 m/s dia = 4 m – મ N=? R V = 5 m/s dia= 2 m
The total discharge (flowrate) from A to B in the figure below is 300 liters/s. Pipe lennthe are: L1= 150 m, and L2 = 450 m. Diameters, are: D1 = 500 mm, and D2 = 250 mm. L1:D1 Q1 Q Q2 L2; D2 Determine [Using Darcy's equation] the headloss [m] and the flowrates (/s] across A-B in pipes 1 and 2 if riyated steel iron pipes are used in the system and flow is FULLY TURBULENT. Flowrate pipe #1 [I/s] =- Flowrate pipe #2 [l/s] =- Headloss pipe #1 [m] =. %3D Headloss pipe #2 [m]
Imagine that the water level in Problem 8.34 rises at a rate of 0.1 cm/s. Knowing the diameter of the tank is 15 cm, what is the average velocity of the water leaving the tank?
The circular water pipes shown in the sketch are flowing full. The velocity of flow (in m/s) in the branch pipe "R" is PI V = 6m/s, dia = 4m - = V = ? R Q V = 5m/s dia = 2m
Water is flowing through a venturimeter shown. The difference in pressure between Point 1 (D = 4cm) and Point 2 (D = 2cm) is measured using open tubes. If h is 50cm, solve the volumetric flowrate. h 下 O 0.00110m^3/s O 0.00162m^3/s O 0.00254m^3/s O 0.00102m^3/s