4. A survey by Women's Health magazine stated that 20% of women said they usedexercise to reduce stress and cope up with the fashion trend physical fitness. A randomsample of 200 women was selected, and 20 said that they used exercise to relievestress. Test the claim at a=0.10Step 1: State the hypotheses.Step 2: The level of significance, one/two-tailed test, degrees of freedomStep 3: Statistical TestStep 4: ComputationStep 5: Decision RuleStep 6: Reject Ho or Failed to Reject HoStep 7: Conclusion

Answered: Image /qna-images/answer/65bdbdc8-025e-4e0d-b61f-fa98d5b47c2b.jpg

Answered: 4. A survey by Women's Health magazine…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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... Done < AA *@ 100% A learn.hawkeslearning.com Question 1 of 5, Step 2 of 3 1/15 Correct 3 A psychology graduate student wants to test the claim that there is a significant difference between the IQs of spouses. To test this claim, she measures the IQs of 9 married couples using a standard IQ test. The results of the IQ tests are listed in the following table. Using a 0.10 level of significance, test the claim that there is a significant difference between the IQs assuming that the population distribution of the paired differences is approximately normal. Let the spouse 1 group be Population 1 and let the spouse 2 group be Population 2. IQs of Married Couples Spouse 105 115 124 98 112 125 105 123 129 1 Spouse 103 113 108 123 105 125 121 95 130 Copy Data Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places. E Tables E Keypad Answer Keyboard Shortcuts Submit Answer EN O 2022 Hawkes Learning LI R H S D B
Need the test statistic & p value. & confidence interval. Thankyou.
We have conducted a one sided hypothesis test with a significance level α = 0.10. We would like to also construct a confidence interval with an equivalent level so that we can compare our results. What should the confidence level of this interval be? (Note: Do not include the percent sign.)
A recent article published by the Wall Street Journal said the Cincinnati airport had the most expensive airfares among the largest airports in the US. While they had some statistics to support this statement, a statistician decided to investigate further. A sample of 46 flights originating in Cincinnati was selected, and the round-trip airfare for each flight was recorded. The sample data is summarized in the StatCrunch output below: With 98% confidence, we estimate the mean airfare for flights out of Cincinnati is between $ and $. (Round the limits of your interval to 4 decimal places.) The mean airfare nationwide was reported as $376 for a round-trip ticket. Does the interval found above support the claim that Cincinnati has airfares which are more expensive than other airports in the US? The interval does not support the claim because the entire interval is not above $376. We can't make this conclusion based on a confidence interval. The interval does not support this claim…
The chancellor wants you to do a research study on the number of hours students report sleeping in a typical day. You select a random and representative sample of 25 students and ask them to report the number of hours they sleep in a typical day. Tehe data below are in hours. 5 7 3 8 9 8 6 4 10 7 9 7 5 11 8 4 2 6 8 6 10 8 6 8 9 Calculate a 95% confidence interval for the sample mean. Round your final answer to the hundredth place. What t score was used in calculating your confidence interval for the question above? *Your analysis of the raw data indicates that 13 of 25 students reported sleeping no more than 7 hours per day* Calculate a 95% confidence interval for the sample proportion. Round to the nearest hundredth place.
A sample of freshman takes a reading comprehension test and their scores are summarized below. Sample scores: 16, 8, 8, 6, 9, 11, 13, 9, 10 a. if the mean for the general population on this test is m=12, can you conclude that this sample is significantly different from the population. Test with a=.05 b. Calculate a 90% confidence interval around your mean.
If one views a test statistic of z=1.03, should the conclusion be to accept the null hypothesis at a 90% confidence level? Explain your answer, thinking carefully about statistical terminology.
CorpPlus is a large corporation with many employees. You work for the human resources department of CorpPlus and want to estimate the population proportion of all employees who say the corporation is a great place to work. So, you will survey a random sample of 95 employees from CorpPlus and ask them whether they think the corporation is a great place to work. Follow the steps below to construct a 99% confidence interval for the population proportion of all employees who say the corporation is a great place to work. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from the random sample. Take Sample Sample size: 0 Point estimate: 0 Critical value: 0 Compute 0.000 Says the corporation is a great place to work Enter the values of the sample size, the point estimate of the population proportion, and the critical value you need for your 99% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you…
Consider a drug that is used to help prevent blood clots in certain patients. In clinical trials, among 5797 patients treated with this drug, 151 developed the adverse reaction of nausea. Use a 0.10 significance level to test the claim that 3% of users develop nausea. Does nausea appear to be a problematic adverse reaction? Question content area bottom Part 1 Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. H0: p≠0.03 H1: p=0.03 B. H0: p=0.03 H1: p<0.03 C. H0: p=0.03 H1: p>0.03 D. H0: p=0.03 H1: p≠0.03 Your answer is correct. Part 2 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is enter your response here. (Round to two decimal places as needed.)
how does increasing the sample size influence the size of the t statistic in a hypothesis test. How does it influence the width of a 95% confidence level?
The critical boundaries for a hypothesis test are z = +1.96 and -1.96. If the z-score for the sample data is z = -1.90, what is the correct statistical decision?
According to a report on consumer fraud and identity theft, 20% of all complaints for a year were for identity theft. In that year, Oregon had 714 complaints of identity theft out of 3449 consumer complaints. Does this data provide enough evidence to show that Oregon had a higher proportion of identity theft than 20%? Test at the 5% level. State the hypotheses. Họ: P ?v Ha: P ? Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .05, reject Ho. O Since the p-value is greater than .05, fail to reject Ho. O Since the p-value is greater than .05, reject Ho- O Since the p-value is less than .05, fail to reject Ho- Interpret the results. O At the 5% level of significance, there is not enough evidence to show that the proportion of complaints due to identity theft in Oregon is less than 20%. O At…

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