The pruning mechanism of a pole saw is shown as it cuts a branch S. For the particular position drawn, the actuating cord is parallel to the pole and carries a tension of 30 lb. Determine the shearing force P applied to the branch by the cutter, the total force supported by the pin at E and the force exerted by member CD. The force exerted by the light return spring at C is small and may be neglected. 3. The pruning mechanism of a pole saw is shown as it cuts a branch S. For the particular position drawn,the actuating cord is parallel to the pole and carries a tension of 30 lb. Determine the shearing force Papplied to the branch by the cutter, the total force supported by the pin at E and the force exerted bymember CD. The force exerted by the light return spring at C is small and may be neglected.20°X20%Ans.P =30 lb20°RE =CD =L75°AB = 1", BC = ED = 3", EB = DC = 44;", DF = 6"

Calculating CD:Taking moment at E:ME=0=-CD(3 Sin(20+20+20))+46.43(9Sin…

Answered: 3. The pruning mechanism of a pole saw…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Concept explainers

Question

The pruning mechanism of a pole saw is shown as it cuts a branch S. For the particular position drawn, the actuating cord is parallel to the pole and carries a tension of 30 lb. Determine the shearing force P applied to the branch by the cutter, the total force supported by the pin at E and the force exerted by member CD. The force exerted by the light return spring at C is small and may be neglected.

3. The pruning mechanism of a pole saw is shown as it cuts a branch S. For the particular position drawn,
the actuating cord is parallel to the pole and carries a tension of 30 lb. Determine the shearing force P
applied to the branch by the cutter, the total force supported by the pin at E and the force exerted by
member CD. The force exerted by the light return spring at C is small and may be neglected.
20°
X20%
Ans.
P =
30 lb
20°
RE =
CD =
L75°
AB = 1", BC = ED = 3", EB = DC = 4
4;", DF = 6"

Expert Solution

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions