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3) SiO2(s) + 2CO(g) Si(s) + 2C02(g) -> Calculate the CO/CO2 ratio in equilibrium for 1250°C and show if SiO2 will be reducted or not in the environment containing %80 CO and %20 CO2. Si(s) +02 (g) = SiO2(s) C (s) + ½ O2 (g) = CO (g) C(s)+ O2(g) = C02(g) AG°- -907100+175T (J) (298-1685 K) AG- -111700 -87.65T (J) (298-2500 K) AGT= -394100 -0.84T (J) (298-2500 K) %3D

3) SiO2(s) + 2CO(g) Si(s) + 2C02(g) -> Calculate the CO/CO2 ratio in equilibrium for 1250°C and show if SiO2 will be reducted or not in the environment containing %80 CO and %20 CO2. Si(s) +02 (g) = SiO2(s) C (s) + ½ O2 (g) = CO (g) C(s)+ O2(g) = C02(g) AG°- -907100+175T (J) (298-1685 K) AG- -111700 -87.65T (J) (298-2500 K) AGT= -394100 -0.84T (J) (298-2500 K) %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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3) SiO2(s) + 2C0(g)→Si(s) + 2CO2(g) Calculate the CO/CO2 ratio in equilibrium for 1250°C and show if SiO2 will be reducted or not in the environment containing %80 CO and %20 CO2. Si(s) +02 (g) = SiO2(s) C (s) + ½ O2 (g)= CO (g) C(s) + O2(g) = CO2(g) AG- -907100+175T (J) (298-1685 K) AG T= -111700-87.65T (J) (298-2500 K) AG°T= -394100 -0.84T (J) (298-2500 K)
Transcribed Image Text:3) SiO2(s) + 2C0(g)→Si(s) + 2CO2(g) Calculate the CO/CO2 ratio in equilibrium for 1250°C and show if SiO2 will be reducted or not in the environment containing %80 CO and %20 CO2. Si(s) +02 (g) = SiO2(s) C (s) + ½ O2 (g)= CO (g) C(s) + O2(g) = CO2(g) AG- -907100+175T (J) (298-1685 K) AG T= -111700-87.65T (J) (298-2500 K) AG°T= -394100 -0.84T (J) (298-2500 K)
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